Question

Consider the equation y=sqrtx and y=x^2-1

Answer 1

The correct answer is 1.5,1.2
the x value should be positive because it's under the sqrt.
the y value is also positive from the first equation.

Answer 2

Answer:

(1.5 , 1.2)

Step-by-step explanation:

we are given system of equation as

$y=\sqrt{x}$

$y=x^2-1$

we can set them equal

and then we can solve for x

$y=x^2-1=\sqrt{x}$

we can take square both sides

$\left(x^2-1\right)^2=\left(\sqrt{x}\right)^2$

now, we can simplify it

$x^4-2x^2+1=x$

$x^4-2x^2-x+1=0$

now, we can draw graph and find x-intercept

so, x-intercepts are

(0.525,0)

(1.49,0)

now, we can find y-value

At x=1.49

$y=1.49^2-1$

$y=1.2$

So, point is (1.49 , 1.2)

or

(1.5 , 1.2)