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aliya0001 [1]
3 years ago
8

Evaluate: (10-(6-4)^2)/2 A. -6 B. 0 C. 3 D. 10

Mathematics
2 answers:
Marta_Voda [28]3 years ago
4 0

Answer:

The answer is C-3

Step-by-step explanation:

marin [14]3 years ago
4 0
Its 3. (10-(2)^2)/2
(10-4)/2=6/2=3
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Y + 2 =1/2(x – 3).<br><br> Please help ?!?
Sidana [21]

first, spread the parenthesis. y+2=1/2x-1.5

second, add 1.5 to both sides. y+3.5=1/2x

third, multiply by 2. 2y+7=x

if you are solving for y, do not do the third step, instead, subtract by 3.5. y=x-3.5

hope this helps!

ANSWER: x=2y+7 or y=x-3.5

6 0
3 years ago
Which of the options below does the month-end review process help with? Select all that apply.
Shkiper50 [21]

The month-end review process help with the following below:

  • Finding transactions with outstanding issues.
  • Dealing with unreconciled accounts.
  • Running payroll.
  • Identifying discrepancies with accounts and starting balances.

<h3>What is Month-end review process?</h3>

This is usually done by the accounting department of an organization and are involved in payrolling.

Outstanding transactions and accounts are also reviewed so as to ensure accuracy.

Read more about Month-end review process here brainly.com/question/24134045

#SPJ1

4 0
1 year ago
Read 2 more answers
9. Using a twenty sided number cube, what is the probability that you will roll an even number or
IceJOKER [234]

Answer:

0.85

Step-by-step explanation:

total samples cases = 20

chances that are even or odd prime are 17 chances

2, 3, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 16, 17, 18, 19, 20

probability = 17/20

= 0.85

3 0
2 years ago
A software developer wants to know how many new computer games people buy each year. Assume a previous study found the standard
Marrrta [24]

Answer:

The minimum sample size required to ensure that the estimate has an error of at most 0.14 at the 95% level of confidence is n=567.

Step-by-step explanation:

We have to calculate the minimum sample size n needed to have a margin of error below 0.14.

The critical value of z for a 95% confidence interval is z=1.96.

To do that, we use the margin of error formula in function of n:

MOE=\dfrac{z\cdot \sigma}{\sqrt{n}}\\\\\\n=\left(\dfrac{z\cdot \sigma}{MOE}\right)^2=\left(\dfrac{1.96\cdot 1.7}{0.14}\right)^2=(23.8)^2=566.42\approx 567

The minimum sample size to have this margin of error is n = 567.

3 0
3 years ago
15. The table below shows the various ways
Kipish [7]

Answer:

45 %  

Step-by-step explanation:

\begin{array}{lc}\textbf{Method} & \textbf{Number}\\\text{Walk} & 36 \\\text{Bus} & 26 \\\text{Car} & 18 \\\text{TOTAL} & \mathbf{80} \\\end{array}\\\text{Percent of walkers} = \dfrac{36}{80} \times 100 \% = \mathbf{45 \, \%}

7 0
3 years ago
Read 2 more answers
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