A bag contains 3 red marbles and 4 blue marbles. a marble is taken at random and replaced. Another marble is taken from the bag. Work out the probability that the two marbles taken from the bag are the same color.
<span>Total number of marbles in the bag is 3 + 4 = 7.<span>The problem asks for the probability of (RR) or (BB).</span>It's worthy to note we are replacing the balls after each draw, which means we always have 7 to draw from</span>Since each draw is independent, we take the product of each event for the total event probability.
P(RR) = 3/7 * 3/7 = 9/49
P(BB) = 4/7 * 4/7 = 16/49
We want to know P(RR) + P(BB)
<span>P(RR) + P(BB) = 9/49 + 16/49 = 25/49</span>
Let's isolate (1/2)x. To do this, subtract 2 from both sides of the equation, obtaining (1/2)x < -7.
Next, multiply both sides by 2 to eliminate the fraction (1/2):
x < -14
1. y < -x - 5......(-3,-4)
2. 5x - 3y < = 15.....all of ur answers satisfy this inequality
Answer:
4.2
Step-by-step explanation:
Answer:
is it proper question I am sorry I canot understand
