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andre [41]
2 years ago
12

~(~p) is always equivalent to 1: q 2: (~(~(~ (~p)))) 3: ~P 4: ~q

Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
7 0
? Wth.....................
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y-y1=m(x-x1)

y-2=1/3(x-3)

y=1/3x+1

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The variable s varies directly as the square of t. When s = 4, t = 12. Nick’s work finding the value of t when s = 48 is shown:
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C - He substituted incorrectly when calculating the constant of variation.

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There are 467 sixth grade students at east side middle school. Each one needs 8 book covers. How many book covers are needed?
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3 years ago
In △ABC, ∠ABC = 60 degrees .
ira [324]

A given<u> shape</u> that is <em>bounded</em> by three <u>sides</u> and has got three <em>internal angles</em> is referred to as a <u>triangle</u>. Thus the <em>value</em> of <u>PB</u> is 8.0 units.

A given <em>shape</em> that is <u>bounded</u> by three<em> sides</em> and has got three <em>internal angles</em> is referred to as a <u>triangl</u>e. Types of <u>triangles</u> include right angle triangle, isosceles triangle, equilateral triangle, acute angle triangle, etc. The sum of the<em> internal angles</em> of any <u>triangle</u> is 180^{o}.

In the given question, point<u> P</u> is <u>center</u> of the given <u>triangle</u> such that <APB = <APC = <BPC = 120^{o}. Such that <u>line</u> PB <em>bisects</em> <ABC into two <u>equal</u> measures of 30^{o}.

Thus;

<ABP = 30^{o}

Thus,

<ABP + <APB + <BAP = 180^{o}

30 + 120 + <BAP = 180^{o}

<BAP = 180^{o} - 150

<BAP = 30^{o}

Apply the <em>Sine rule</em> to determine the value of PB, such that;

\frac{a}{SinA} = \frac{b}{SinB}

\frac{8}{Sin 30} = \frac{PB}{Sin 30}

BP = \frac{8*Sin 30}{Sin 30}

    = 8

BP = 8.0

Therefore, the value of <u>PB</u> = 8 units.

For more clarifications on Sine rule, visit: brainly.com/question/27174058

#SPJ1

5 0
1 year ago
PLZZZZZZZZZZZZZZZZZZZZZZ HELP!<br><br> -3x+4=-2 show your work!!!
Katyanochek1 [597]

Answer:

x=2

Step-by-step explanation:

5 0
2 years ago
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