Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
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Answer:
80
Step-by-step explanation:
that would be the area of the YARD the fence is surround area is width times length.
if they are really asking the area of the fence itself there isnt enough info here. (I think)
Answer:
A
Step-by-step explanation:
the answer is
x+15=28
x=28-15
x= 13
Just divide the two
1780/60=29.66 round to 30
Hope this helps have a nice nite