Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have

Therefore, the probability of event A is given by

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Answer:
it would be w7
Step-by-step explanation:
because to get w you mulitply w with 7
so all that you need to do is put the 7 next to the w
because mathematicians are known to be lazzy so they do not put the multiplication sign, instead the put it next to each other meaning that it is mulitplied
simple awnser for the simple question
Answer:
is
Step-by-step explanation:
so I calculated this and I got a fraction
I got 64/135
Are you trying to set up the equation?
the equation: 24(2)+6=n
Answer:
#1. 40
#2. y=221.5
#3 197 ft
#4. 30 min
Step-by-step explanation: