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avanturin [10]
3 years ago
12

Part B

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

idk im dumb

Step-by-step explanation:

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Consider two events such that P(A) = 1/3, P(B) = 4/5, and P(A ∩ B) = 4/15. Are events A and B independent events?
RSB [31]
Yes, they are independent because P(A) ⋅ P(B) = P(A ∩ B)
4 0
3 years ago
How can you rewrite the problem so that the divisor is a whole number?<br> 0.21 divided by 17.66
Leona [35]

Answer: 21 divided by 1766

Step-by-step explanation:

just try to remove the decimal points which mean 0.21 to 21 and 17.66 to 1766

4 0
3 years ago
Help me please 123432323
gladu [14]

Answer: About 0.46

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Prove that dx/x^4 +4=π/8
insens350 [35]
\displaystyle\int_0^\infty\frac{\mathrm dx}{x^4+4}

Consider the complex-valued function

f(z)=\dfrac1{z^4+4}

which has simple poles at each of the fourth roots of -4. If \omega^4=-4, then

\omega^4=4e^{i\pi}\implies\omega=\sqrt2e^{i(\pi+2\pi k)/4} where k=0,1,2,3

Now consider a semicircular contour centered at the origin with radius R, where the diameter is affixed to the real axis. Let C denote the perimeter of the contour, with \gamma_R denoting the semicircular part of the contour and \gamma denoting the part of the contour that lies in the real axis.

\displaystyle\int_Cf(z)\,\mathrm dz=\left\{\int_{\gamma_R}+\int_\gamma\right\}f(z)\,\mathrm dz

and we'll be considering what happens as R\to\infty. Clearly, the latter integral will be correspond exactly to the integral of \dfrac1{x^4+4} over the entire real line. Meanwhile, taking z=Re^{it}, we have

\displaystyle\left|\int_{\gamma_R}\frac{\mathrm dz}{z^4+4}\right|=\left|\int_0^{2\pi}\frac{iRe^{it}}{R^4e^{4it}+4}\,\mathrm dt\right|\le\frac{2\pi R}{R^4+4}

and as R\to\infty, we see that the above integral must approach 0.

Now, by the residue theorem, the value of the contour integral over the entirety of C is given by 2\pi i times the sum of the residues at the poles within the region; in this case, there are only two simple poles to consider when k=0,1.

\mathrm{Res}\left(f(z),\sqrt2e^{i\pi/4}\right)=\displaystyle\lim_{z\to\sqrt2e^{i\pi/4}}f(z)(z-\sqrt2e^{i\pi/4})=-\frac1{16}(1+i)
\mathrm{Res}\left(f(z),\sqrt2e^{i3\pi/4}\right)=\displaystyle\lim_{z\to\sqrt2e^{i3\pi/4}}f(z)(z-\sqrt2e^{i3\pi/4})=\dfrac1{16}(1-i)

So we have

\displaystyle\int_Cf(z)\,\mathrm dz=\int_{\gamma_R}f(z)\,\mathrm dz+\int_\gamma f(z)\,\mathrm dz
\displaystyle=0+2\pi i\sum_{z=z_k}\mathrm{Res}(f(z),z_k) (where z_k are the poles surrounded by C)
=2\pi i\left(-\dfrac1{16}(1+i)+\dfrac1{16}(1-i)\right)
=\dfrac\pi4

Presumably, we wanted to show that

\displaystyle\int_0^\infty\frac{\mathrm dx}{x^4+4}=\frac\pi8

This integrand is even, so

\displaystyle\int_0^\infty\frac{\mathrm dx}{x^4+4}=\frac12\int_{-\infty}^\infty\frac{\mathrm dx}{x^4+4}=\frac12\frac\pi4=\frac\pi8

as required.
6 0
4 years ago
A cell phone package charges $39 even if 0 minutes are used during the month.Each additional minute of talk time adds a $0.07.Wr
vodomira [7]

Answer:

Total monthly cost (x) = $39 + ($0.07/min)x

Step-by-step explanation:

The y-intercept is $39.  The slope is ($0.07/minute)x, where x is the number of talk minutes.  Thus:

Total monthly cost (x) = $39 + ($0.07/min)x, where x is the number of talk minutes.

6 0
4 years ago
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