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2 years ago

Y=2x+6, 3y=x-2 solve for unknown variables

Mathematics

2 answers:

11Alexandr11 [23.1K]2 years ago

3 0

Step: Solvey=2x+6for y:

y=2x+6

Step: Substitute2x+6foryin3y=x−2:

3y=x−2

3(2x+6)=x−2

6x+18=x−2(Simplify both sides of the equation)

6x+18+−x=x−2+−x(Add -x to both sides)

5x+18=−2

5x+18+−18=−2+−18(Add -18 to both sides)

5x=−20

5x/5=−20/5

(Divide both sides by 5)

x=−4

Step: Substitute−4forxiny=2x+6:

y=2x+6

y=(2)(−4)+6

y=−2(Simplify both sides of the equation)

Answer:

x=−4 and y=−2

I hope it helps you

MakcuM [25]2 years ago

3 0

X=-4
Y=-2
Step by step explanation

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2 years ago

(t+9)20=140 what is t

GarryVolchara [31]

Answer:

t=-2

Step-by-step explanation:

(t+9)20=140

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8 0

2 years ago

Read 2 more answers

I need help with #11

Troyanec [42]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template in mind, let's take a peek at this function

$\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}$

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically

8 0

3 years ago

Read 2 more answers

Please answer clear i need answers now please

Salsk061 [2.6K]

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