Given
<span>c'(q)=dc/dq=0.006q^2-0.6q+70
Integrate marginal cost to get cost function
c(q)=0.002q^3-0.3q^2+70q+C (C is a constant)
Fixed cost = 2000 means that C=2000.
or
c(q)=</span>0.002q^3-0.3q^2+70q+2000
Average cost=c(q)/q, for q=200,
=(0.002*q^3-0.3*q^2+70*q+2000)/q
=20000/200
=100
Answer: Average cost is $100
Answer:
22 units
Step-by-step explanation:
The perimeter of a rectangle is 2(width + length)
In this case width = 2z + 2 and length = 3z + 3
replacing everything known:
110 = 2(2z + 2 + 3z + 3)
110/2 = (5z + 5)
55 = 5z + 5
55 - 5 = 5z
50 = 5z
10 = z
Segment PQ is the same as SR = 2z + 2
Replacing z = 10
PQ = 2(10) + 2
I am assuming the equation is as follows

Since the constant 10 is -10 this tells us we are going to have different signs + - after you have factored the equation.
First thing first. Think of two numbers that will give you the
product(The answer after two numbers are multiplied) of -10 and the
sum(Two numbers added together) of +3. I get the 3 from the 3x.
We know 5 x -2 = -10 and the sum 5 + -2 = +3
With that said, we found our two factors
(x + 5)(x - 2)
Now write them as zeros and solve for x
x + 5 = 0
x = -5
x - 2 = 0
x = 2
So the zeros are -5 and 2.
It has a coefficient of 4 :)
Let’s convert 3 kilograms to 3000 grams just to make things easier.
650 * 4 = 2600 grams. This is the total weight of the 4 blocks.
To find the weight of the final block, 3000 - 2600 = 400 grams