If you borrow $500 at 5% for two years, how much will you pay back by the end of the term?

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

8 0

Answer:

Your estimated monthly payments are $22 and you will pay $26 in interest over the life of the loan.

Step-by-step explanation:

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Write the number 0.000938 in scientific notion.

ss7ja [257]

0.000938 in scientific notion.

First we need to move the decimal to its right and we need a number which is between 1-10.

0.000938
00.00938
000.0938
0000.938
00009.38

We moved the decimal 4 times and to the right so it will be negative. -4.

9.38 × 10^-4

Scientific notation of 0.000938 is 9.38 × 10^-4.

Check:-

9.38 × 10^-4 = 0.000938
0.000938 = 0.000938
Correct!

Scientific notation of 0.000938 is 9.38 × 10^-4.

6 0

3 years ago

Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p

Dima020 [189]

Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

d) Standard error

e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

Step-by-step explanation:

a) This distribution is called the sampling distribution of sample proportions (p-hat).

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

$\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058$

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

$\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667$