Answer: the variable is p=6 .
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable
Answer:
18.1 cm
Step-by-step explanation:
AD segment breakup: 11=4+7
Pythagorean Theorem:
7^2+b^2=16^2
49+b^2=256
x^2=207
b=sqrt(207)
b=3sqrt(23)
Pythagorean Theorem:
11^2+3sqrt(23)^2=c^2
121+207=c^2
328=c^2
18.11=c
So the length of AC is around 18.1 cm
Answer:
5.5m^2
the area of just the trench is 5.5 m^2
Step-by-step explanation:
The Area of trench only is the total area(trench and garden) minus the Area of garden
Area of trench only = total area(trench and garden) - Area of garden
Area = length × breadth
Substituting the given dimensions;
Total area = 3.5 × 3 = 10.5 m^2
Area of garden = 2.5×2 = 5 m^2
Area of trench only = 10.5 m^2 - 5 m^2
Area of trench only = 5.5m^2
the area of just the trench is 5.5 m^2
Answer:
20cm
Step-by-step explanation:
Frame L&W: 25×20
PictureL&W:20×16
25-20=5
Length of Picture frame=5
Length of Picture frame=4
5×4=20cm²
To find area you multiply length by width
Answer:
y = (x + 6)² - 1
Step-by-step explanation:
So there are two ways of doing it, completing the square or partial factoring (which is what i prefer and will show)
so we will get x first:
x^2+12x
We are factoring x
x(x+12)
Now you do x=-12/2
x=-6
Now that you have x, you plg that back into the equation to get y
y= -6^2 +12(-6) +35
= 36-36+35
=-1
Put into vertex form
y = (x + 6)² - 1
