What transformation can be used to transform figure ABCDEF to A"B"C"D"E"F

I need help with these questions

Lunna [17]

Answer:

5 , 6, 2

Step-by-step explanation:

cause they da same

5 0

3 years ago

Which scales are equivalent to the scale 1cm to 5km? More than one is the right answer

Oduvanchick [21]

The answer would be A because each side is being multiplied by 3

8 0

3 years ago

Read 2 more answers

(1) The ratios 18:3 and 6:1 are equivalent. Why?

aliya0001 [1]

Answer:

Because if you take 18:3 and divide both sides by 3, you will get 6:1

Step-by-step explanation:

Because 18:3 divided by 3 on both sides equals 6:1, also 6:1 times 3 on both sides equals 18:3.

6 0

3 years ago

Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

6 0

3 years ago

The length, in millimeters of each side of a square shaped electronic chip is a rational number. What statement is true about th

AVprozaik [17]

Answer:

The diagonal is irrational because it is a product of a rational and an irrational number

Step-by-step explanation:

The options are not given. However, the question is still answerable.

Given

Shape: Square

Length: Rational

Since the side length is said to be rational, I'll answer the question based on whether the diagonal is rational or not.

Having said that:

The diagonal (d) of a square with side length (l) is calculated using Pythagoras theorem.

$d^2 = l^2 + l^2$

$d^2 = 2l^2$

Take positive square root of both sides

$d = \sqrt{2l^2}$

Split:

$d = \sqrt{2} * \sqrt{l^2}$

$d = \sqrt{2} *l$

Recall that the side length (l) is rational.

However, $\sqrt 2$ is irrational.

So, the product of l and $\sqrt 2$ will be irrational

Hence:

The diagonal is irrational

8 0

3 years ago