Answer:
a. 1620-x^2
b. x=810
c. Maximum value revenue=$656,100
Step-by-step explanation:
(a) Total revenue from sale of x thousand candy bars
P(x)=162 - x/10
Price of a candy bar=p(x)/100 in dollars
1000 candy bars will be sold for
=1000×p(x)/100
=10*p(x)
x thousand candy bars will be
Revenue=price × quantity
=10p(x)*x
=10(162-x/10) * x
=10( 1620-x/10) * x
=1620-x * x
=1620x-x^2
R(x)=1620x-x^2
(b) Value of x that leads to maximum revenue
R(x)=1620x-x^2
R'(x)=1620-2x
If R'(x)=0
Then,
1620-2x=0
1620=2x
Divide both sides by 2
810=x
x=810
(C) find the maximum revenue
R(x)=1620x-x^2
R(810)=1620x-x^2
=1620(810)-810^2
=1,312,200-656,100
=$656,100
Answer:
6 < x < 30
Step-by-step explanation:
By the Hinge Theorem, we know that
Angle BAC > Angle DAC
The two triangles that make the diamond have two equal sides. The third side of the upper triangle is longer than the third side if the lower triangle. To fit in the longer side, line AB had to be pushed outwards, forming a larger angle.
When we compare the two angles 48 and (2x-12), we now know that 48 is larger.
48 > 2x-12
48+12 > 2x
60 > 2x
60/2 > x
x < 30
Furthermore, angle DAC can't be negative or zero
2x - 12 > 0
2x > 12
x > 6
Answer:
Step-by-step explanation:
The vaulu of A oh! I know that the vaulu of A is Z! Hope this helps! Please give me brailyest!?
Answer:
the answer is 9
Step-by-step explanation:
if you divide it together you will get 9
Answer:
x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.
Step-by-step explanation:
Let x be the length of wire that is cut to form a circle within the 5050 wire, so 5050 - x would be the length to form a square.
A circle with perimeter of x would have a radius of x/(2π), and its area would be
A square with perimeter of 5050 - x would have side length of (5050 - x)/4, and its area would be
The total combined area of the square and circles is
To find the maximum and minimum of this, we just take the 1st derivative, and set it to 0
Multiple both sides by 8π and we have
At x = 2221.5:
= 392720 + 500026 = 892746 [/tex]
At x = 0, 
At x = 5050, 
As 892746 < 1593906 < 2029424, x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.
