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AfilCa [17]
3 years ago
13

Find the common ratio for the series equation 50, -10, 2 , -2/5, ...

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

-1/5.

Step-by-step explanation:

Common ratio = -10/50 = 2/-10 = -2/5 / 2 = -1/5.

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A nutrition laboratory wants to construct a 95% confidence interval for the mean sodium content of "reduced sodium" hot dogs. A
tatuchka [14]

Answer:

n > 96

Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg

Step-by-step explanation:

Given;

Standard deviation r= 25mg

Width of confidence interval w= 10mg

Confidence interval of 95%

Margin of error E = w/2 = 10mg/2 = 5mg

Z at 95% = 1.96

Margin of error E = Z(r/√n)

n = (Z×r/E)^2

n = (1.96 × 25/5)^2

n = (9.8)^2

n = 96.04

n > 96

Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg

6 0
3 years ago
What is 15 minutes later than 2:50
blsea [12.9K]

Answer:

3:05

I hope this helps

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
For which function is the ordered pair (5,10) not a solution ?
PilotLPTM [1.2K]

Answer:

D)

Step-by-step explanation:

Because

a)  10 = 2(5) = 10

b) 10 = 5 + 5 = 10

c) 10 = 15 -5 = 10

d) 10 = 5 - 5 = 0  the result is not equivalent

4 0
3 years ago
Read 2 more answers
Paris is 4,000 miles away from Columbus, Ohio. It takes an airplane 8 hours to fly there. What is the speed of the airplane
eimsori [14]

Answer:

500

Step-by-step explanation:

if you take 4,000 miles and divide it by 8 hours, it will give you 500, so that how we figure the speed.

The final answer is 500.

5 0
2 years ago
The rate at which sand is poured into a bag is modeled by the function r given by r(t)=15t−2t2, where r(t) is measured in millil
balu736 [363]

Answer:

35 mililiters

Step-by-step explanation:

Given

r(t) = 15t - 2t^2

Required

Accumulated amount from t = 0 to 2

This implies that, we substitute the values of t from 0 to 2 in the function

r(0) = 15*0 - 2*0^2= 0

r(1) = 15*1 - 2*1^2= 13

r(2) = 15*2 - 2*2^2= 22

The accumulated sand (r) is:

t = r(0) + r(1) + r(2)

r = 0 + 13 + 22

r = 35

6 0
3 years ago
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