The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Answer:
I think the answer is 33
Step-by-step explanation:
Extremely sorry if it's wrong
Answer
Point 1 (2, 8)
Point 2 (5, 20)
Step-by-step explanation:
Since we are given the x values of 2 and 5, substitute them in the equation and you will get 8 and 20.
Answer:
it is b
Step-by-step explanation:
hope i helped
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