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3 years ago

Larry read 1.5 times as much as he did on Monday how many pages did he read on Wednesday if he read 24 pages on Monday?

Mathematics

1 answer:

Andreas93 [3]3 years ago

3 0

Answer:

Step-by-step explanation:

umm add divide or multiply both numbers

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The equations y = 2x - 5 and y = 13.x

Neporo4naja [7]

Answer:

g5 is the sultugbji also dont forget the sulution bro

Step-by-step explanation:

huh

3 0

3 years ago

A sin^3theta+b cos^3theta=sintheta costheta and a sintheta-b costheta=0 then prove a^2+b^2=1

frozen [14]

Answer:

Proof in explanation

Step-by-step explanation:

Trigonometric Identities

The basic trigonometric identity is:

$\sin^2\theta+\cos^2\theta=1$

We'll use it and some basic algebra to prove that, given:

$a sin^3\theta+b cos^3\theta=sin\theta cos\theta$

And

$a\sin\theta-b\cos\theta=0$

Then

$a^2+b^2=1$

From the equation:

$a\sin\theta-b\cos\theta=0$

We have:

$a\sin\theta=b\cos\theta\qquad [1]$

The equation

$a sin^3\theta+b cos^3\theta=sin\theta cos\theta$

Can be rewritten as

$a\sin\theta \sin^2\theta+b \cos^3\theta=\sin\theta \cos\theta$

Replacing [1]:

$b\cos\theta \sin^2\theta+b \cos^3\theta=\sin\theta \cos\theta$

Taking the common factor:

$b\cos\theta (\sin^2\theta+ \cos^2\theta)=\sin\theta \cos\theta$

The expression in parentheses is 1, thus:

$b\cos\theta =\sin\theta \cos\theta$

Dividing by $\cos\theta$

$b=\sin\theta$

Replacing in

$a\sin\theta=b\cos\theta$

We have

$a\sin\theta=\sin\theta\cos\theta$

Dividing by $\sin\theta$

$a=\cos\theta$

Now:

$a^2+b^2=(\cos\theta)^2+(\sin\theta)^2$

This expression is 1, thus it's proven:

$\boxed{a^2+b^2=1}$

6 0

3 years ago

Jenna bought 4 composition notebooks and 3 pocket folders from the

Anettt [7]

Answer:

Step-by-step explanation:

She paid 3.42 for 3 pocket folders in total she paid 9.85 so 9.85-3.42 should give u the total for the 4 composition notebooks then you would divide that total the 9.85-3.42 which is 6.43 divided by 4 is 1.90

4 0

4 years ago

Convert 111110 base two to base eight

Gre4nikov [31]

Answer: I got 76.

Step-by-step explanation:

8 0

3 years ago

Find the first five terms of the recursive sequence an=-6an-1 where a1=4.5

grandymaker [24]

Answer:

4.5, -27, 162,-972, 5832

Step-by-step explanation:

The given recursive definition is,

$a_n=-6a_{n-1}, a_1=4.5$

This will form a geometric sequence with first term 4.5 and common ratio r=-6.

When n=2, we have:

$a_2=-6a_1 \\ \implies \: a_2=-6 \times 4.5 = - 27$

When n=3, we get:

$a_3=-6a_2 \\ \implies \: a_3=-6 \times - 27 = 162$

When n=4, we get:

$a_4=-6a_3 \\ \implies \: a_4=-6 \times 162 = - 972$

When n=5, we get:

$a_5=-6a_4 \\ \implies \: a_5=-6 \times - 972 = 5832$

Therefore the first five terms are:

4.5, -27, 162,-972, 5832

3 0

4 years ago

Larry read 1.5 times as much as he did on Monday how many pages did he read on Wednesday if he read 24 pages on Monday?​

Larry read 1.5 times as much as he did on Monday how many pages did he read on Wednesday if he read 24 pages on Monday?