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Umnica [9.8K]
3 years ago
6

Which of these are arithmetic sequences?

Mathematics
1 answer:
evablogger [386]3 years ago
5 0

A sequence of numbers is said to arithmetic if any couple of adjacent terms differ by the same number. That number is said to be the common difference of the sequence. Let's see what the differences are for each sequence:

First sequence

Difference between the first two terms:

1 - (-3) = 4

Difference between the third and second terms:

5 - 1 = 4

Difference between the fourth and third terms:

9-5 = 4

The difference is constant, so this sequence is an arithmetic sequence.

Second sequence

Difference between the first two terms:

2 - 1 = 1

Difference between the third and second terms:

4-2 = 2

The difference is not constant, so this sequence is not an arithmetic sequence.

Third sequence

Difference between the first two terms:

-12 - 4 = -16

Difference between the third and second terms:

36 - (-12) = 36+12 = 48

The difference is not constant, so this sequence is not an arithmetic sequence.

Fourth sequence

Difference between the first two terms:

14 - 7 = 7

Difference between the third and second terms:

21 - 14 = 7

Difference between the fourth and third terms:

28 - 21 = 7

The difference is constant, so this sequence is an arithmetic sequence.

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Find the value of the expression when b= 9 c= 5 and d=10 ............ ½d + c² - b
Minchanka [31]

Answer:

1/2d+c^2-b = 21

Step-by-st ep explanation:

= 1/2(10) + 5^2 -9

= 5 + 25 - 9

= 30 - 9

= 21

4 0
2 years ago
5. You are scheduling your classes for next year. There are 4 required classes: a physical education
puteri [66]
<h3>Answer:   450</h3>

==============================================

Explanation:

For now, let's consider we can only select 2 classes instead of 4. Let's say we only had to worry about PE and history.

Let A,B,C,D,E represent the five PE classes.

Let F,G,H,I,J,K represent the six history classes.

If you arrange the letters in a table, you should get 5*6 = 30 different inner boxes of the table. Refer to the diagram below.

Each two letter code in the table represents the 2 class combo. For example, BG means you picked PE class B and history class G.

This idea can be extend to selecting 3 classes. Imagine that each of the codes in the table are laid along the side of a new table. So we'd have a table of 30 rows. Then lay out 5 columns (say with letters L,M,N,O,P) to represent the 5 English classes. You would get a table of 30*5 = 150 different combos here. Of course you shouldn't actually make such a table since it's so large, but I'm simply just saying for you to imagine one. All of the tables mentioned are completely optional. A tree diagram is another way to organize things, though tree diagrams tend to get cumbersome.

Anyway, we would have 5*6*5 = 30*5 = 150 different ways to pick the PE, history and English classes. We can extend this out to include the math classes as well.

-------------------------

In short, all we do is multiply the given values together:

5*6*5*3 = 30*15 = 450

This idea is known as the counting principle.

5 0
2 years ago
WRITE USING ALGEBRA
AysviL [449]
F+b= x
(f+3)+(b+3)=x
(f-2)-(b-2)=x
8 0
2 years ago
Solve for 2 unknowns : 3a+4b=9 ; 2a+2b=6
BARSIC [14]
Let us take the second equation first
2a + 2b = 6
Dividing both sides by 2 we get
a + b = 3
a = 3 - b
Putting the value of a in the first equation we get
3a + 4b = 9
3(3 - b) + 4b = 9
9 - 3b + 4b = 9
b = 9 - 9
   = 0
Now putting the value of b in the second equation we get
a + b = 3
a + 0 = 3
a = 3
So the value of the unknown variable a is 3 and the value of the unknown variable b is 0.

3 0
3 years ago
Find the product of <br><br> (5.226)•(0.037)=
Alenkasestr [34]

Answer:

ans is 0.193362................

6 0
3 years ago
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