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3 years ago

8

An elevator descends into a mine shaft at the rate of 6 m/min. If the descend starts from 20 meter above the ground level, how l

ong will it take to reach - 340m?

1 answer:

levacccp [35]3 years ago

5 0

60 minutes. Take how far it is above ground (20 m) and add it to the absolute value of how far it is below ground (340 m) to get 360 meters, which you divide by the rate of descent (6 m/min) to get 60 minutes.

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A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th

Olegator [25]

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

$y = \frac{340110}{1 + 377e^{-0.259t}}$

Solving (a): 1998

Year 1998 means that:

$t =1998 - 1980$

$t =18$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*18}}$

$y = \frac{340110}{1 + 377e^{-4.662}}$

$y = \frac{340110}{1 + 3.562}$

$y = \frac{340110}{4.562}$

$y = 74553$ --- approximated

Solving (b): 2003

Year 2003 means that:

$t = 2003 - 1980$

$t =23$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*23}}$

$y = \frac{340110}{1 + 377e^{-5.957}}$

$y = \frac{340110}{1 + 0.976}$

$y = \frac{340110}{1.976}$

$y = 172120$ --- approximated

Solving (c): 2006

Year 2006 means that:

$t = 2006 - 1980$

$t =26$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*26}}$

$y = \frac{340110}{1 + 377e^{-6.734}}$

$y = \frac{340110}{1 + 0.4485}$

$y = \frac{340110}{1.4485}$

$y = 234802$ --- approximated

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2 years ago

Covert 2/3 years to months

natali 33 [55]

Multiply by 12 so 8

thank you hope this helps

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3 years ago

Read 2 more answers

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Answer:

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Step-by-step explanation:

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3 years ago

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lyudmila [28]

Answer:

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2 years ago

What is the measure of angle TSU?

goldfiish [28.3K]

Answer:

80

Step-by-step explanation:

Angle VSU = 100. Angles TSU is a linear pair with angle VSU so adding them together equals 180. 180-100=80.

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3 years ago