Answer:
3rd answer
Step-by-step explanation:
Two dice with #s 1-6
To roll a sum of 7, the 2 numbers have to add up to 7.
First die Second die
1 6
2 5
3 4
4 3
5 2
6 1
Each of those combinations adds up to 7. There are 6 of them. The total number of possibilities of rolls is 6 x 6 = 36.
Probability is favorable outcomes / total outcomes, so it's 6/36 = 1/6
Answer:
what do you need?
Step-by-step explanation:
The events A and B are independent events, and the values of P(A) and P(B) are 7/12 and 1/2, respectively
<h3>The value of P(A)</h3>
The event A is given as:
A : Sum greater than 6
In the sample space of a roll of two dice, there are 21 outcomes that are greater than 6, out of a total of 36 outcomes
This means that:
P(A) = 21/36
Simplify
P(A) = 7/12
<h3>The value of P(B)</h3>
The event B is given as:
B : Sum is divisible by 2
In the sample space of a roll of two dice, there are 18 outcomes that are divisible by 2, out of a total of 36 outcomes
This means that:
P(B) = 18/36
Simplify
P(B) = 1/2
Hence, the probability values of P(A) and P(B) are 7/12 and 1/2, respectively
Read more about probability at:
brainly.com/question/251701
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A^2 = b^2 + c^2 - 2bc cos a
= 11^2 + 5^2 - 2*5*11 cos 40
= 7.86 to 2 DP's
to find the remaining angles use the sine rule:-
a / sin A = b / sin B so
7.857/ sin 40 = 11 / sin B
sin B = 11 sin40 / 7.857 = 0.8999
<B = 64 degrees
so <C = 180 - 64-40 = 76 degrees
