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nataly862011 [7]
3 years ago
15

2x+7=27 i need help nolie .

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0

Answer:

x=10

Step-by-step explanation:

2x+7=27

2x=27-7

2x=20

2x/2=20/2

x=10

Mnenie [13.5K]3 years ago
4 0

Answer:

x=10

Step-by-step explanation:

2 x 10 = 20+7=27 therefore x=10

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3 years ago
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Bianca has a paper route. She delivers 100 newspapers every 2 days. How many newspapers does she deliver in a week?
Vlad [161]

We know Bianca delivers 100 newspapers every 2 days.

So we must find out how many papers she delivers in 1 day.

100 ÷ 2 = 50

Bianca delivers 50 papers in 1 day.

Now we must multiply that by 7.

50 × 7 = 350

We get 350 papers per week.

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2 years ago
If F(x) and G(x) are two functions such that F(G(x)) = x then F(x) and G(x) are ..?
lana [24]
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The idea is that whatever the output of g(x) is, it's plugged into f(x) and the initial input is the result. So g(x) takes a step forward and f(x) takes a step back undoing everything g(x) did. Which is exactly what an inverse operation does. 
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2 years ago
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1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n
Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 70% of fatalities involve an intoxicated driver, hence p = 0.7.
  • A sample of 15 fatalities is taken, hence n = 15.

The probability is:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

Hence

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061

P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186

P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700

P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916

P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305

P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047

Then:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

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2 years ago
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3. D
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Slope of graph d = 81/27 = 3
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2 years ago
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