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Vilka [71]
3 years ago
9

$28 lunches; 15% tip

Mathematics
2 answers:
Masja [62]3 years ago
8 0

Answer:

Paid a total of $32.20 ($28 for the lunches and $4.20 for the tip)

Step-by-step explanation:

<u>Solve to find the amount of the tip</u>

–Since 28 is given, all you have to do is find 15% of 28 to find how much the tip was:

15% of 28 ⇒ 0.15 × 28 = 4.2

Answer: $4.20

<u />

<u>Solve to find the total amount paid</u>

–Now, add 28 (amount paid for the lunches) and 4.2 (amount of the tip) together to find the total amount that was paid:

28 + 4.2 = 32.2

<u>Final Answer:</u> Paid a total of $32.20 ($28 for the lunches and $4.20 for a tip)

<em></em>

<em>Hope this helps!</em> :)

nikklg [1K]3 years ago
6 0

Answer: $4.20 tip

Step-by-step explanation:

15% of 28 is 4.2

Using a calculator, you can find the value of the tip by multiplying 0.15 by 28.

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<u>KA</u>

5 0
3 years ago
An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh
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Answer:

Speed of the plane in still air: 779\; {\rm km \cdot h^{-1}}.

Windspeed: 100\; {\rm km \cdot h^{-1}}.

Step-by-step explanation:

Assume that x\; {\rm km \cdot h^{-1}} is the speed of the plane in still air, and that y\; {\rm km \cdot h^{-1}} is the speed of the wind.

  • When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be (x - y)\; {\rm km \cdot h^{-1}}.
  • When this plane is travelling in the same direction as the wind, the ground speed of this plane would be (x + y)\; {\rm km \cdot h^{-1}}.

The question states that when going against the wind (v = (x - y)\; {\rm km \cdot h^{-1}},) the plane travels 6111\; {\rm km} in 9\; {\rm h}. Hence, 9\, (x - y) = 6111.

Similarly, since the plane travels 7911\; {\rm km} in 9\; {\rm h} when travelling in the same direction as the wind (v = (x + y)\; {\rm km \cdot h^{-1}},) 9\, (x + y) = 7911.

Add the two equations to eliminate y. Subtract the second equation from the first to eliminate x. Solve this system of equations for x and y: x = 779 and y = 100.

Hence, the speed of this plane in still air would be 779\; {\rm km \cdot h^{-1}}, whereas the speed of the wind would be 100\; {\rm km \cdot h^{-1}}.

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2 years ago
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Step-by-step explanation:

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