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The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for is 9.
Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and for 8<t<11.
A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.
B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.
C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.
D) In this we have to find the function at when m belongs to
the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.
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Answer:
(x-8)(x+7)
Step-by-step explanation:
using quadratic formula we have
x=
we have:
x^2-x-56=0
a= 1 b=-1 c=-56
so we have:
x=(-(-1)+-sqrt(1^1-4*(1)*(-56)))/(2*1)
x=1+-sqrt(1-4*(-56))/(2)
x=(1+-sqrt(225))/2
x=(1+-15)/2
so we have the roots:
x1=(1+15)/2 =8
x2=(1-15)/2=-7
so the answer is (x-8)(x+7)