Answer
can we get a picture of the problem ?
Explanation:
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
<span>Any computer or device on a network that can be addressed on the local network is referred to as a: node.</span>
Answer:
The offset
Explanation:
In the question, we understand that the original text is HELLO and the encrypted text is OLSSV.
It should be noted that O replaced H, L replaced E, S replaced L and V replacement O.
This is made possible by a term refered to as offset.
The offset is used to determine the character that will replace another when it is encrypted.
7 characters after H is O; this is same for every other characters in the text.
