The aNSWER IS 41..AM I RIGHT?
2- 11
3- each hour she gets 8.75
4- .80
5- 3
You would multiply 100 by 6 to get the 6 away from m. this leaves m on one side of the equal sign and 6•100 on the other. multiply that out, which is 600. so m=600.
The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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