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dangina [55]
3 years ago
15

Astronauts in orbit feel weightless because

Advanced Placement (AP)
1 answer:
Nesterboy [21]3 years ago
8 0
There is no gravity and the air is denser
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The crime scheme and suspect are very similar in the pattern meaning it is suspect number 2

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I could be wrong but this one seems to make the most sense so D. none
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E Both A & C, need an explanation?
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2 years ago
Which of the following is the same as (V3+V2)2 ?
Drupady [299]
Solution. To check whether the vectors are linearly independent, we must answer the following question: if a linear combination of the vectors is the zero vector, is it necessarily true that all the coefficients are zeros?
Suppose that
x 1 ⃗v 1 + x 2 ⃗v 2 + x 3 ( ⃗v 1 + ⃗v 2 + ⃗v 3 ) = ⃗0
(a linear combination of the vectors is the zero vector). Is it necessarily true that x1 =x2 =x3 =0?
We have
x1⃗v1 + x2⃗v2 + x3(⃗v1 + ⃗v2 + ⃗v3) = x1⃗v1 + x2⃗v2 + x3⃗v1 + x3⃗v2 + x3⃗v3
=(x1 + x3)⃗v1 + (x2 + x3)⃗v2 + x3⃗v3 = ⃗0.
Since ⃗v1, ⃗v2, and ⃗v3 are linearly independent, we must have the coeffi-
cients of the linear combination equal to 0, that is, we must have
x1 + x3 = 0 x2 + x3 = 0 ,
x3 = 0
from which it follows that we must have x1 = x2 = x3 = 0. Hence the
vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
Answer. The vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
4 0
3 years ago
Question below: (thanks!)
wel

Answer:

Frequency of SS dominant individuals is 0.57

Explanation:

The total population of rabbit is 650

Out of 650 rabbit, nearly 39 have recessive allele "s".

Hence, frequency of recessive genotype = \frac{39}{650} = 0.06

Frequency of recessive allele = \sqrt{0.06}

q = \sqrt{0.06} = 0.245

Frequency of dominant trait allele "S" p = 1-q = 1-0.245 = 0.755

Frequency of SS dominant individuals is p^{2} = 0.755^2 = 0.57

5 0
2 years ago
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