<span>¿Sólo entiendes español o puedo responder en inglés?</span>
Answer:
all real numbers
Step-by-step explanation:
Here is the solution to the first inequality:
3(2x +1) > 21 . . . . . . given
6x +3 > 21 . . . . . . . . eliminate parentheses
6x > 18 . . . . . . . . . . .subtract 3
x > 3 . . . . . . . . . . . . divide by 6
This is all numbers to the right of 3 on the number line.
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The solution to the second inequality is ...
4x +3 < 3x + 7 . . . . given
x < 4 . . . . . . . . . . . . subtract 3x+3
This is all numbers to the left of 4 on the number line.
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The conjunction in the system of inequalities is "or", so we are looking for values of x that will satisfy at least one of the conditions. <em>Any value of x</em> will satisfy one or the other or both of these inequalities. The solution is all real numbers.
Answer:
x=12
Step-by-step explanation:
a^2 + b^2 = c^2
5^2 + b^2 = 13^2
25 + b^2 = 169
b^2= 144
b=12 Therefore,
x=12
