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Anna35 [415]
3 years ago
11

Anybody wanna help me on this?

Mathematics
1 answer:
igomit [66]3 years ago
7 0

Answer:

(0,-2) , (2,1) , (4,4)

Step-by-step explanation:

those are the points, now connect then with a line

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-15+p+3=17

p would equal 29

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5 trapezoid 6 polygon 7 Parrelogram 8squaare

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A store sells a box of pencils for $3. Each box contains 24 pencils. How much will it cost a teacher to buy pencils
alex41 [277]

Answer:

$6

Step-by-step explanation:

This is for one pencil to each student. Since each box is $3, and she has 25 students, you would figure out how many students are left out with one box, and since you only have one left, you only need one more box. That would mean two boxes, so $3x2= $6

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4. According to statistics reported on IN-CORP a surprising number of motor vehicles are not covered by insurance. Sample result
son4ous [18]

Answer:

a) 0.23

b) The 95% confidence interval for the population proportion is (0.1717, 0.2883).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Point estimate

The point estimate is:

\pi = \frac{46}{200} = 0.23

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.23 - 1.96\sqrt{\frac{0.23*0.77}{200}} = 0.1717

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.23 + 1.96\sqrt{\frac{0.23*0.77}{200}} = 0.2883

The 95% confidence interval for the population proportion is (0.1717, 0.2883).

5 0
3 years ago
9. Plot the points A (-2,3), B(2,-3), C(2,3) ,D(-2,3) join the points and find the distance between each point.
pav-90 [236]

Answer:

AB=7.21 unit

BC=6 unit

CD=7.21 unit

AD= 6 unit

AC=4 unit

BD=4 unit

Step-by-step explanation:

Coordinates of A =(-2,3)

Coordinates of B = (2,-3)

Coordinates of C = (2,3)

Coordinates of D =(-2,-3)

Distance formula :d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A=(x_1,y_1)=(-2,3)\\B=(x_2,y_2)=(2,-3)\\AB = \sqrt{(2+2)^2+(-3-3)^2}

AB=7.21 unit

B=(x_1,y_1)=(2,-3)\\C=(x_2,y_2)=(2,3)\\BC=\sqrt{(2-2)^2+(3+3)^2}

BC=6

C=(x_1,y_1)=(2,3)\\D=(x_2,y_2)=(-2,-3)\\CD=\sqrt{(-2-2)^2+(-3-3)^2}

CD=7.21

A=(x_1,y_1)=(-2,3)\\D=(x_2,y_2)=(-2,-3)\\AD=\sqrt{(-2+2)^2+(-3-3)^2}

AD=6

A=(x_1,y_1)=(-2,3)\\C=(x_2,y_2)=(2,3)

AC=\sqrt{(2+2)^2+(3-3)^2}

AC=4

B=(x_1,y_1)=(2,-3)\\D=(x_2,y_2)=(-2,-3)

BD=\sqrt{(-2-2)^2+(-3+3)^2}

BD=4

4 0
3 years ago
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