What is the remainder when (2x^3 - 5x^2 + 3x + 7) is divided by (x - 2)?

Mathematics

2 answers:

Stells [14]2 years ago

6 0

Answer:

<h2>remainder = 9</h2>

<u>Step-by-step explanation:</u>

(x - 2) => x = 2

f(x) = f(2)

= 2x³ - 5x² + 3x + 7

= 2(2)³ - 5(2)² + 3(2) + 7

= 2×8 - 5×4 + 6 + 7

= 16 - 20 + 6 + 7

= 29 - 20

= 9

german2 years ago

4 0

Answer:

Step-by-step explanation:

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$\displaystyle y = Asec(Bx - C) + D$

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

$\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}$

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Extended Information on the trigonometric function

$\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|$

NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.

I am joyous to assist you anytime.