Answer:
The three quadratic equations are;
x² + 3 = 0
x² + 2·x + 1 = 0
x² + 3·x + 2 = 0
Step-by-step explanation:
1) A quadratic equation with no real solution is one with an imaginary solution such as one with a negative square root
We can write the quadratic equation as follows;
x² + 3 = 0
∴ x = √(-3) = √(-1) ×√3 = i·√(3)
Therefore, the equation f(x) = x² + 3, has no real root at f(x) = 0
2) A quadratic that has 1 real root is of the form;
(x + 1)² = 0
The root of the equation is x = -1 from (x + 1) = ((-1) + 1)² = 0²
Which gives;
(x + 1)² = (x + 1)·(x + 1) = x² + 2·x + 1 = 0
Therefore, the quadratic (x + 1)² = 0 has only one real root
3) A quadratic that has 2 real root is of the form;
(x + 1)·(x + 2) = 0
x² + x + 2·x + 2 = 0
x² + 3·x + 2 = 0
Therefore, the three quadratic equations are;
x² + 3 = 0
x² + 2·x + 1 = 0
x² + 3·x + 2 = 0
Answer:
Step-by-step explanation:
Nick's age = x years
Lina's age =3*x = 3x
After 6 years,
Lina's age = 3x + 6
Nick's age = x + 6
3x + 6 = 2*(x+6)
3x + 6 = 2*x + 2*6
3x + 6 = 2x + 12 {Subtract 6 form both sides}
3x +6 - 6 = 2x + 12 - 6
3x = 2x + 6 {subtract 2x from both sides}
3x - 2x = 2x + 6 - 2x
x = 6
Nick's age = 6 years
Lina's age =3*6 = 18 years
Answer:
31
Step-by-step explanation:
A. n+q=45n+25q=20. That should be the correct answer
Answer:
x = 3
Step-by-step explanation:
x + 9x + 5 = 35
=> x + 9x = 35 - 5
=> x + 9x = 30
=> 10x = 30
=> x = 30/10
=> x = 3