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3 years ago

Simply 8t + 6r - 3t + 2r

Mathematics

2 answers:

ella [17]3 years ago

8 0

Answer:

The answer would be 8r + 5t

ehidna [41]3 years ago

4 0

Answer: 8r+5t

Step-by-step explanation:

8t + 6r - 3t + 2r

8t-3t= 5t

6r+2r=8r

= 8r+5t

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the sum of two mixed numbers is 5 1/2. the differenceof mixed numbers is 3. both numbers have a denominator of 4. what are the t

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Step-by-step explanation:

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3 years ago

Question 9

IgorC [24]

The answer is (C) the middle one

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Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

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$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

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3 years ago

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andrew11 [14]

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3 years ago

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Enzo and Beatriz are playing games at their local arcade. Incredibly, Enzo wins 55 tickets from every game, and Beatriz wins 111

madam [21]

Answer:

101

Step-by-step explanation:

Note that

$55=5\cdot 11;$
$1111=11\cdot 101.$

Here these two numbers have the common divisor 11. Find the least common multuply:

$LCM(55,1111)=11\cdot 5\cdot 101=5555.$

This means that the minimum number of games that Enzo could have played will be

$\dfrac{5555}{55}=101.$

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