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abruzzese [7]
3 years ago
8

John is painting a picture.He has green, red, yellow, purple, orange and blue paint. He wants to use four different colors on th

is picture. If order does not matter, how many ways can John pick four colors for his picture, if one of them is green?
a
6
b
15
c
10
d
4
Mathematics
2 answers:
Rom4ik [11]3 years ago
7 0

Answer:

C 10

Step-by-step explanation:

He has 6 colours to choose 3 from.

One of them is green, so he just needs to choose 2 from the remaining 5.

That's,

5C2 = 10

uysha [10]3 years ago
5 0

Answer:

c) 10

Step-by-step explanation:

You do 5 C 3 ( because you are choosing 3 from the remaining 5).

5C3 = 5!/(3!2!) = 10

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Ksenya-84 [330]

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5 0
3 years ago
If m∠A = 72°, m∠B = 32°, and c = 8, what are the measures of the remaining sides and angle?
mixas84 [53]

The laws of cosine and sine and the given parameters can be used to

calculate the measure of angles and distances.

Correct responses:

Question 1: A. m∠C = 76°, a = 7.84, b = 4.37

Question 2: C. 1 triangle

Question 3: D. 31.2 miles

Question 4: A. b = 10.799

Question 5: C. 28.9°

<h3>Methods and calculations used to obtain the above responses </h3>

Question 1:

If m∠A = 72°

m∠B = 32°

c = 8

Therefore;

m∠C = 180° - 72° - 32° = 76°

\displaystyle \frac{a}{sin(72^{\circ})} = \mathbf{ \frac{8}{sin(76^{\circ})} }

\displaystyle a = \mathbf{\frac{8}{sin(76^{\circ})} \times sin(72^{\circ})} \approx 7.84

\displaystyle b =  \frac{8}{sin(76^{\circ})} \times sin(32^{\circ}) \approx 4.37

The correct option is therefore;

  • <u>A. m∠C = 76°, a ≈ 7.84, b ≈ 4.37</u>

Question 2

The given parameters are;

\displaystyle B = \mathbf{ \frac{\pi}{6} }

\displaystyle \frac{\pi}{6} = 30^{\circ}

a = 20

b = 10

Therefore,  by the law of cosine we have;

  • b² = a² + c² - 2·a·c·cos(B)

Which gives;

10² = 20² + c² - 2×20×c×cos(30°)

100 = 400 + c² - 20·c·(√3)

c² - 20·√3 ·c + 300 = 0

\displaystyle c = \frac{20 \cdot \sqrt{3} \pm\sqrt{1200-4 \times 1 \times 300}  }{2 \times 1}  = \mathbf{ 10 \cdot \sqrt{3} }

Therefore, given that <em>c</em> has only one value, the three sides of the triangle are known, and the number of triangles unique triangles by Side-Side-Side description is; <u>C. 1 triangle</u>

Question 3

The distance between the weather station = 24 miles

The bearing of the storm from weather station A = N17°W

The bearing of the storm from weather station B = N48°W

The angle formed at point <em>C</em> in ΔABC  is therefore;

108° - 42° - 107° = 31°

By sine rule, we have;

\displaystyle \frac{24}{sin(31^{\circ})} =\mathbf{\frac{x}{sin(42^{\circ})} }

Where:

x = The distance from weather station <em>A</em> from the storm

Which gives;

\displaystyle x = \frac{24}{sin(31^{\circ})} \times sin(42^{\circ}) \approx \mathbf{31.2 \ miles}

  • The distance from weather station <em>A</em> from the storm is <u>D. 31.2 miles</u>

Question 4

∠A = 52°

∠C = 57°

Side BC = 9

Therefore;

∠B = 180° - 52° - 57° = 71°

∠B = 71°

According to the law of sines, we have;

\displaystyle \frac{b}{sin(71^{\circ})}= \mathbf{ \frac{9}{sin(52^{\circ})}  }

Therefore;

\displaystyle b = \frac{9}{sin(52^{\circ})}   \times sin(71^{\circ}) \approx \mathbf{ 10.799}

  • The correct option is; <u>A. b = 10.799</u>

Question 5

Given:

Label of the vertex of the triangle formed are; The golfer, spectator, hole

Distance from the golfer to the hole = 200 yards

Distance from the golfer to the spectator = 140 yards

Vertex angle at the spectator = 110°

By using the law of sines, we have;

\displaystyle \frac{200}{sin(110^{\circ})} = \frac{140}{sine \  of \ the \ angle  \ at \ the \ hole,  \ \phi}

Therefore;

\displaystyle sin(\phi) = \mathbf{ \frac{140}{200} \times sin(110^{\circ})} = 0.7 \times sin(110^{\circ})

The angle at the hole, ∅ = arcsin(0.7×sin(110°)) ≈ 41.13°

Therefore;

The angle that the golfer has = 180° - 110° - 41.1° = 28.9°

  • The angle that the golfer has between the spectator and the hole is <u>C. 28.9°</u>

Learn more about law of cosine and sine here:

brainly.com/question/2384846

brainly.com/question/16555495

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2 years ago
If x = 4y + 21y and y = 14 + 5, what is 3x × 7? No need to show your work.
podryga [215]

y = 19

x = 4(19) + 21(19) = 76 + 399 = 475

3(475) × 7

1425 × 7

9975 <--- answer.

Hope this helped!

Nate

7 0
3 years ago
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Vinil7 [7]
The answer is 0.0055 rounded
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What is the length of the line segment with endpoints (−3,8) and (7, 8) ?
Fudgin [204]
Ur answer would be 10 units
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