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andrew11 [14]
3 years ago
7

(44/5 ÷ 3 5/7) – (11/3)2

Mathematics
2 answers:
qwelly [4]3 years ago
5 0

Answer:

HI

Step-by-step explanation:

jeyben [28]3 years ago
4 0

Answer:

2x(0z - 12)

Step-by-step explanation:

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Find thy slope of the line passing through the given point (2,0),(-6,8)
astraxan [27]

Answer:

slope = - 1

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (2, 0) and (x₂, y₂ ) = (- 6, 8)

m = \frac{8-0}{-6-2} = \frac{8}{-8} = - 1

8 0
3 years ago
okay so I don't really understand how to change a decimal to a fraction and the teacher never really explained it to us and she
Fofino [41]

\bf 0.2121\overline{21}\qquad \qquad \qquad x=0.2121\overline{21}\\\\ -------------------------------\\\\ \stackrel{\textit{moving the 21 to the left}}{\stackrel{100\cdot x}{100\cdot 0.2121\overline{21}}}\implies  21.2121\overline{21}\implies  \begin{array}{llll} 21&+&0.2121\overline{21}\\ 21&+&x \end{array} \\\\\\ therefore\qquad \qquad 100x  = 21+x\implies 99x=21 \\\\\\ x=\cfrac{21}{99}\implies x=\stackrel{simplified}{\cfrac{7}{33}}

5 0
4 years ago
How many units long is a line segment whose endpoints have coordinates (-3,7) and (2,-5)?
Ilia_Sergeevich [38]

Answer:

D = 13 units

Step-by-step explanation:

<u><em>Using Distance Formula to find the length.</em></u>

Distance Formula = \sqrt{(x2-x1)^2+(y2-y1)^2}

D = \sqrt{(2+3)^2+(-5-7)^2}

D = \sqrt{(5)^2+(-12)^2}

D = \sqrt{25+144}

D = \sqrt{169}

D = 13 units

8 0
3 years ago
Read 2 more answers
How do you find the complex and real roots for x^4-3x^2+2=0
pogonyaev
X^4 - 3x^2 + 2 = 0
(x^2 - 2)(x^2 - 1) = 0

so either x^2 - 2 = 0  or x^2 - 1 = 0

so x^2 = 2 or x^2 = 1

so x = sqrt 2 , - sqrt2, 1 , -1   Answer

all the roots are real
6 0
4 years ago
the area of a rectangle is 30 to the square root of 3750 square inches, and the length is 3 to the square root of 250 inches. wh
uranmaximum [27]
<h3><u>Answer</u><u>:</u></h3>

  • \sf { width =10 \sqrt{15} \:inches}

<h3><u>Solution</u><u>:</u></h3>

<em>We are given that:</em>

  • Area of rectangle is 30√3570
  • Length of the rectangle is 3√250

<u>Area </u><u>of </u><u>rectangle </u><u>is </u><u>given </u><u>by:</u>

\implies\quad{\pmb{ \sf{Area = length\times width}} }

<u>Hence, putting the values in the formula:</u>

\implies\quad \sf{ A = l\times w}

\implies\quad \sf{ 30\sqrt{3750}=3\sqrt{250}\times w}

\implies\quad \sf{3\sqrt{250}\times w = 30\sqrt{3750} }

\implies\quad \sf{ w =\dfrac{30\sqrt{3750}}{3\sqrt{250}}}

\implies\quad \sf{ w =10\dfrac{\sqrt{3750}}{\sqrt{250}}}

\implies\quad \sf{ w = 10\times\sqrt{\dfrac{3750}{250}}}

\implies\quad \underline{\underline{\pmb{\sf{ w =10\sqrt{15}}}}}

8 0
3 years ago
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