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2 years ago

(44/5 ÷ 3 5/7) – (11/3)2

Mathematics

2 answers:

qwelly [4]2 years ago

5 0

Answer:

Step-by-step explanation:

jeyben [28]2 years ago

4 0

Answer:

2x(0z - 12)

Step-by-step explanation:

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Urgent help needed, thanks!

SSSSS [86.1K]

Answer:

2/5 is the rest of the shirts

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2 years ago

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Can someone help me please

wolverine [178]

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90 degrees

angles are measured in degrees

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2 years ago

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Find the value of X. Please help!!

harkovskaia [24]

Answer:

x = 91

Step-by-step explanation:

The opposite angles of an inscribed quadrilateral are supplementary, that is

∠ A + ∠ C = 180, thus

x + 89 = 180 ( subtract 89 from both sides )

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3 years ago

Last summer, winky's waterpark kept track of the number of park visitors each day.

Montano1993 [528]

As per the given data 100, 150, 200, 250, 300, 350 the range of the data set is 250.

<h3>What is range?</h3>

It is defined as the difference between the maximum value in the data set to the minimum value in the data set.

We have:

Last summer, Winky's watermark kept track of the number of park visitors each day.

The data given:

100, 150, 200, 250, 300, 350

As we know range is a statistical measure which is the difference between maximum and minimum value.

Range = maximum value in data set—minimum value in data set

Range = 350 - 100 = 250

Thus, as per the given data 100, 150, 200, 250, 300, 350 the range of the data set is 250.

Learn more about the range here:

brainly.com/question/17553524

#SPJ1

5 0

1 year ago

Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.

sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

$\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ · X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

So, $\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ · X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Isolating the X, we have

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ - $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Resolving:

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]$

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X= $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ ⁻¹· $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

$\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ · $\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]$ = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a= $\frac{2}{11}$ ; b= $\frac{7}{33}$ ; c= $\frac{-1}{11}$ and d= $\frac{-3}{11}$ . Substituting:

X= $\left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11} \end{array}\right]$ · $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Multiplying the matrices, we have

X= $\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11} \end{array}\right]$

6 0

3 years ago