Answer:
0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean 490 mg and variance of 400.
This means that 
What is the probability that a randomly selected pill contains at least 500 mg of minerals?
This is 1 subtracted by the p-value of Z when X = 500. So
has a p-value of 0.6915.
1 - 0.6915 = 0.3085
0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals
Answer:
-0.6
-0.66267
Step-by-step explanation:
Estimating the product :
Using compatible number :
-3 * 0.2
__ 0.2
* ___-3
______
_ - 0.6
______
-3 * 0.2 = 0.6
The exact product :
-3.33(0.199).
Using calculator :
-3.33(0.199) = - 0.66267
Answer:
The true statements are:
B. Interquartile ranges are not significantly impacted by outliers
C. Lower and upper quartiles are needed to find the interquartile range
E. The data values should be listed in order before trying to find the interquartile range
Step-by-step explanation:
The interquartile range is the difference between the first and third quartiles
Steps to find the interquartile range:
- Put the numbers in order
- Find the median Place parentheses around the numbers before and after the median
- Find Q1 and Q3 which are the medians of the data before and after the median of all data
- Subtract Q1 from Q3 to find the interquartile range
The interquartile range is not sensitive to outliers
Now let us find the true statements
A. Subtract the lowest and highest values to find the interquartile range ⇒ NOT true (<em>because the interquartial range is the difference between the lower and upper quartiles</em>)
B. Interquartile ranges are not significantly impacted by outliers ⇒ True <em>(because it does not depends on the smallest and largest data)</em>
<em />
C. Lower and upper quartiles are needed to find the interquartile range ⇒ True <em>(because IQR = Q3 - Q2)</em>
<em />
D. A small interquartile range means the data is spread far away from the median ⇒ NOT true (<em>because a small interquartile means data is not spread far away from the median</em>)
E. The data values should be listed in order before trying to find the interquartile range ⇒ True <em>(because we can find the interquartial range by finding the values of the upper and lower quartiles)</em>
Answer: Answer Number 1; Line AB is similar to
line EF
Line BC is similar to line FG
Line CD is similar to line GH
Line DA is similar to line HE
Step-by-step explanation: First and foremost both
quadrilaterals are similar but of varying dimensions.
If we label both trapezoids as ABCD and EFGH
respectively, then it follows that the corresponding
lines (as stated in the answer above) would also be
similar.
Same applies to the four angles in the interior of the
trapezoids.
Number 2, Angle A equals Angle E
Angle B equals Angle F
Angle C equals Angle G
Angle D equals Angle H
Number 3,
If the scale factor between both figures is 2:3, then
for every length of a side in figure ABCD, the
corresponding side in figure EFGH would be
multiplied by 3/2.
Therefore if AD is 8cm, then EH equals 8 x 3/2
That gives us 12cm.
If GH is 6cm, then DC equals 6 x 2/3. That gives
us 4cm.
If AB is 3 times the length of DC, then AB equals 3
x 4, that gives us 12cm.
If AB is 12cm, then EF equals 12 x 3/2. That gives
us 18cm.
Take note that the shapes are both isosceles
trapezoids, o we have two sides of equal length, AD
and BC in the first figure and then EH and FG in the
other figure.
The first trapezoid has sides 8cm, 12cm, 8cm and
4cm. The perimeter is given as 8+12+8+4 32cm.
The second trapezoid has sides 12cm, 18cm, 12cm
and 6cm. The perimeter is given as 12+18+12+6=
48cm.
