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Naddik [55]
3 years ago
10

Assume that random guesses are made for six multiple choice questions on an SAT test, so that there are n = 6 trials, each with

probability of success (correct) given by
p=0.35. Find the indicated probability for the number of correct answers.
Find the probability that the number of correct answers is fewer than 4.
P(X<4)=0
(Round to four decimal places as needed)
Mathematics
1 answer:
IceJOKER [234]3 years ago
3 0

Answer:

0.9830 = 98.30%

Step-by-step explanation:

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Answer:

One: Median = 2

Two: Mean = 3.25

Step-by-step explanation:

One

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\frac{4}{2\sqrt3+\sqrt5}\cdot\frac{2\sqrt3-\sqrt5}{2\sqrt3-\sqrt5}=\frac{8\sqrt3-4\sqrt5}{(2\sqrt3)^2-(\sqrt5)^2}=\frac{8\sqrt3-4\sqrt5}{4\cdot3-5}=\frac{8\sqrt3-4\sqrt5}{12-5}\\\\=\frac{8\sqrt3-4\sqrt5}{7}
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