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DanielleElmas [232]
4 years ago
11

I need help with this question asap pleaseeeeee

Mathematics
2 answers:
Harman [31]4 years ago
6 0

Answer:

y = 3\sqrt{7}

Step-by-step explanation:

The two inner right triangles are similar, thus the ratios of corresponding sides are equal, that is

\frac{y}{9} = \frac{7}{y} ( cross- multiply )

y² = 63 ( take the square root of both sides )

y = \sqrt{63} = \sqrt{9(7)} = \sqrt{9} × \sqrt{7} = 3\sqrt{7}

makkiz [27]4 years ago
3 0
You can use the pythagorian theorem here:
The corner on the top side is 90 degrees too. So that means (9+7)^2 = A^2 + B^2. The two triangles against each other are the same, but bigger. That means that the left side is 9/16 out of the whole and the right side is 7/16 out of the whole So back to the pythagorean theorem (9+7)^2 = 256. Multiply that number by one of the two numbers before. I will take 9/16, the left side. 256x9/16 = 144. Take the square root of that, 12, and then you have the length of that side. Then use pythagorean theorem again. C^2 = 9^2 + 12^2
C^2 = 225.
C= 15
Seen as C stands for y, there is your answer
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Answer:

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Part b: p-value is 0.00003

Part c: value of p is less that a we reject the null hypothesis.

Step-by-step explanation:

Part a

number of business owners=20%  x n

number of business owners= 0.2x 60

number of business owners=12

Part b

H0: p=0.46

H1: p<0.46

Here

n=60, \hat{p}=0.2, p=0.46

So test statistics is given as

                        z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}\\z=\frac{0.20-0.46}{\sqrt{\frac{0.46(1-0.46)}{60}}}\\z=\frac{-0.26}{0.064}\\z=-4.04

p-value is P(z<-4.04)= 0.00003

Part c

As value of p is less that a we reject the null hypothesis.

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3 years ago
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Answer:

Step-by-step explanation:

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What is the least common multiple of 2, 6, and 15?
VLD [36.1K]

Answer:

30

Step-by-step explanation:

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Answer:

B

Step-by-step explanation:

x + 3y = 7 → (1)

3x + 2y = 0 → (2)

Multiplying (1) by - 3 and adding to (2) will eliminate x

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Add (2) and (3) term by term to eliminate x

0 - 7y = - 21

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Substituting into (1)

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