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Gre4nikov [31]
3 years ago
5

Someone plz help me I will give brainliest

Mathematics
2 answers:
wel3 years ago
6 0
It is D because whenever you take away the zero the amount of both numbers would be the same and adding it to the second one would keep it the same. This is a known fact for all decimals the end in zero you can add as many and take away is money but it really only matters as to what the real numbers are they don’t include zero!
aliina [53]3 years ago
3 0

Answer:

I think it is D

Step-by-step explanation:

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Find the value of x.
vichka [17]

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3 years ago
Helpppp please anyone. I don't understand
vovikov84 [41]
The area is 21cm squared. u would have to find the length of the bottom triangle which is 14. than multiply that by the height which is 3. finally divide that all by 2 and youll get the area
7 0
3 years ago
In his free time, Gary spends 7 hours per week on the Internet and 10 hours per week playing video games. If Gary has five hours
Katyanochek1 [597]

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Step-by-step explanation:

3 0
3 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
Which is the best name for numbers that describe distances on a map?
Vinvika [58]

Answer: Mapping and Cartography

Step-by-step explanation:

Hope this helps:)

4 0
3 years ago
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