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lapo4ka [179]
3 years ago
7

5x5 ( easy points lol )

Mathematics
2 answers:
Afina-wow [57]3 years ago
7 0
25 thanks for the points happy early birthday
oksian1 [2.3K]3 years ago
6 0

Answer:

25

Step-by-step explanation:

thanks for the points I only need 1 more to reach the next rank now

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The triangle below is equilateral. Find the length of side x to the nearest tenth.
Gemiola [76]

Answer:

\sqrt{\frac{15}{2} } or 2.738

Step-by-step explanation:

Let’s just look at the triangle on the top with the \sqrt{10} on the top and x on the bottom. (Basically the top half to the equilateral triangle)

There is a small square in the bottom right corner, which indicates that this triangle is a right triangle. This means that we can use the Pythagorean Theorem: a^{2} +b^{2} =c^{2}

We know that \sqrt{10} is our hypotenuse, and therefore our c in our equation. Let’s say that x=a in our equation. Therefore we are left to find b. However, b is half the length of the side of the original equilateral triangle. An equilateral triangle means that all three sides are the same length. Therefore our side would also be \sqrt{10} units long. However we know that b is half of that value, so b=\frac{1}{2}(\sqrt{10}) or \frac{\sqrt{10} }{2}

Plugging these values into the equation:

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x^{2}=\sqrt{10} ^{2}-\frac{\sqrt{10} }{2} ^{2}

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