Answer:
5, 6
Step-by-step explanation :
We can factor a -2 and an x^2 out of this using GCF.
<h3><u>-2x^2(x - 3) is what we're left with, and is the fully factored form.</u></h3>
Where is the question. though
Hello!
hint: we can rewrite your function as below:
<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π =
=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)
</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:
<span>"4P=π"
Hope this Helps! Have A Wonderful Day! :)</span>
