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shutvik [7]
3 years ago
5

Suppose one painter can paint the entire house in twelve hours, and the second painter takes eight hours to paint a similarly-si

zed house. how long would it take the two painters together to paint the house?
Mathematics
1 answer:
Anton [14]3 years ago
6 0
There is a formula for this:
Time = (Worker1 Time * Worker2 Time) / (Worker1 Time + Worker2 Time)

Time = (12 * 8) / (12 + 8)
Time = 96 / 20
Time = 4.8 Hours

Source:http://www.1728.org/work.htm







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Each container has a base of 4 1/4 yds by 1 2/3 yds. What is the area covered by all the containers?
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Answer:

See Explanation

Step-by-step explanation:

Given

Base Dimension

Length = 4\frac{1}{4}yd

Width = 1\frac{2}{3}yd

Required

The base area of all containers

First, calculate the base area of 1 container.

This is calculated as:

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Express as improper fraction

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So, we have:

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So, we have:

Total = n * Area

Total= n * \frac{85}{12}yd^2

--------------------------------------------------------------------------------------------

Assume n is 3 (i.e. 3 containers)

The total area is:

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--------------------------------------------------------------------------------------------

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