ANSWER PLZZZZZZ!!!!!!!!!!!!!!!

Mathematics

2 answers:

meriva2 years ago

5 0

Answer:

length=(3x-2)

Step-by-step explanation:

area of rectangle=length*breadth

3x^2 + 7x - 6=length * (x+3)

3x^2 +(9-2)x -6=length *(x+3)

3x^2+9x-2x-6=length*(x+3)

3x(x+3)-2(x+3)=length*(x+3)

(x+3)(3x-2)=length*(x+3)

(x+3)(3x-2)/(x+3)=length

(3x-2)=length

Bad White [126]2 years ago

3 0

Answer:

(3x - 2)

Step-by-step explanation:

Given that the area A = length × width

A = 3x² + 7x - 6 ← factor to obtain length

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 3 × - 6 = - 18 and sum = + 7

The factors are + 9 and - 2

Use these factors to split the x- term

3x² + 9x - 2x - 6 ( factor the first/second and third/fourth terms )

= 3x(x + 3) - 2(x + 3) ← factor out (x + 3) from each term

= (x + 3)(3x - 2)

We know (x + 3) is the width , then (3x - 2) is the length

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Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If pos

Kamila [148]

Answer:

Step-by-step explanation:

The fractions are: $\frac{1}{5}$ and $\frac{2}{3}$ . Let's take a look at the denominators: 5 and 3. The LCD of 5 and 3 is 15. 5x3=15, 3x5=15. So now we would multiply the denominators to make them the same number like this: $\frac{5}{15}$ and $\frac{10}{15}$ . Remember that if you multiply the denominator by a certain number, you must multiply the numerator by the same number as well. For example, in $\frac{2}{3}$ , we multiply 3 by 5 and 2 by 5. Same number. Now with that out of the way, let's work on the equation: $\frac{1}{5}$ + $\frac{2}{3}$ . We know it is the same as $\frac{5}{15}$ and $\frac{10}{15}$ . So now all we do is add the numerators together: 5+10=15 or $\frac{15}{15}$ . Now we have to reduce the fraction. $\frac{15}{15}$ can be reduced to 3 by dividing 15 by 5=3. The final fraction is $\frac{3}{3}$ or can be simply put as 3 since 3/3 is a whole number. That's it - you're done!