Let f(x)=18/1+3^e-0.1x What is the point of maximum growth rate for the logistic function f(x)? Show all work. Round your answer
1 answer:
Answer:
(0, 4.5)
Step-by-step explanation:
*The equation can be put into Desmos, to find the point, but the work to prove it is here*
f(x)=c/1+Ae^-Bx
Y=C
C=18 A=3 -B=-0.1
*Replace x with 0 in the equation, so you know 0 is the x value, and it leads you to the y value*
f(0)=18/1+3e^-o.1(0)
= 18/1+3e^0
=18/1+3(1)
=18/1+3
=18/4
=4.5
x=0 y=4.5
Maximum growth rate = (x,y) --> (0, 4.5)
Hope this helps:))!!
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Answer:
The amount in the account in the beginning of the 6th year is $6375 .
Step-by-step explanation:
Formula
As given
You invest $5000 in an account at 5.5% per year simple interest.
Principle = $ 5000
Rate = 5.5 %
Time = 5 years
(As calculate amount in the account for beginning of 6th year.)
Putting all the values in the formula
Simple interest = $ 1375
Amount = Principle + Simple interest
Putting values in the above formula
Amount = $5000 + $1375
Amount = $ 6375
Therefore the amount in the account in the beginning of the 6th year is $ 6375 .