Answer:
could not be the same
Step-by-step explanation:
Given that approximately US drivers are agewise as follows:
<25 13.2
25-45 37.7%
>45 49.1%
Observations are made for a sample of 200 fatal accidents.
Let us create hypotheses as
(Two tailed chi square test at 5% significance level)
Age <25 25-45 >45
Expected 13.2 37.7 49.1 100
Observed 42 80 78 200
Expected no 26.4 75.4 98.2 200
Chi square 9.218181818 0.280636605 4.155193483 13.65401191
df = 2
p value = 0.001084
Since p <0.05 we reject null hypothesis
At the 0.05 level, the age distribution of drivers involved in fatal accidents within the state could not be the same as the age distribution of all US drivers as there seems to be significant difference.
Answer:
The answer to the question is
μx + (σx/4)
Step-by-step explanation:
The sample mean that is one standard deviations above the population mean is given by
value = μx + (Number of standard deviations)
(σx/√n)
value = μx + 1 (σx/√16)=
= μx + (σx/4) =
Where
μx = Population mean
σx = Population standard deviation
n = Sample size
The standard error of the mean is
σ/√n =σ/√16 = σ/4
The standard of error is an indication of the expected error in the mean of a sample from the mean of the population.
The above statements is based on the central limit theorem, which states that, in particular instances the normalized sum of independent random variables becomes closer and closer to those of normal distribution regardless of the variation in the sample of the variables
Answer: (740)((1+0.0065)^132-1)/(0.0065)(1+0.0065)^132
Step-by-step explanation:
To solve this, you must subtract .56 from -1.64. Then divide that by -5.5x. So the answer is .4
Answer:
Probability both are nervous around strangers = 0.0049
Probability at least one is nervous around strangers = 0.1302
Step-by-step explanation:
Let probability a person selected in the population is nervous around strangers = P
P = 7%
P = 
P = 0.07
Let probability a person selected in the population is not nervous around strangers = P'
P' = 1 - P
P' = 1 - 0.07
P' = 0.93
(i) probability of the first person selected is nervous around strangers = P
probability of the second person selected is nervous around strangers = P
Probability both are nervous around strangers = (P × P)
= 0.07 × 0.07
= 0.0049
(ii) Probability at least one is nervous around strangers = ( probability the first person is nervous around strangers AND the second person is not nervous around strangers ) OR ( probability the second person is nervous around strangers AND the first person is not nervous around strangers)
This implies,
Probability at least one is nervous around strangers = (P × P') or (P × P')
= (0.07 × 0.93) + (0.07 × 0.93)
= 0.0651 + 0.0651
= 0.1302
