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soldier1979 [14.2K]
3 years ago
7

Please help!!!!! I'm very confused how to do this​

Mathematics
1 answer:
Alla [95]3 years ago
5 0

Answer:

Is there a formula?

Step-by-step explanation:

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Approximately 13.2% of US drivers are younger than age 25, with 37.7% in the 25-44 age group, and 49.1% in the 45-and-over-categ
Elan Coil [88]

Answer:

could not be the same

Step-by-step explanation:

Given that approximately US drivers are agewise as follows:

<25   13.2

25-45   37.7%

>45   49.1%

Observations are made for a sample of 200 fatal accidents.

Let us create hypotheses as

H_0:  Proportions age wise are the same as for US drivers\\H_a: Proportions are different

(Two tailed chi square test at 5% significance level)

Age <25 25-45 >45  

Expected 13.2 37.7 49.1 100

Observed 42 80 78 200

Expected no  26.4 75.4 98.2 200

Chi square 9.218181818 0.280636605 4.155193483 13.65401191

df = 2

p value = 0.001084

Since p <0.05 we reject null hypothesis

At the  0.05 level, the age distribution of drivers involved in fatal accidents within the state could not be the same as the age distribution of all US drivers as there seems to be significant difference.

5 0
3 years ago
If, for a random sample of 16 days, the sample mean ends up being exactly one standard deviation of x above the population mean,
Rudik [331]

Answer:

The answer to the question is

μx + (σx/4)

Step-by-step explanation:

The sample mean that is one standard deviations above the population mean  is given by

value = μx + (Number of standard deviations)

(σx/√n)

value = μx + 1 (σx/√16)=

=  μx + (σx/4) =

Where

μx = Population mean

σx = Population standard deviation

n = Sample size

The standard error of the mean is

σ/√n =σ/√16 = σ/4

The standard of error is an indication of the expected error in the mean of a sample from the mean of the population.

The above statements is based on the central limit theorem, which states that, in particular instances the normalized sum of independent random variables becomes closer and closer to those of  normal distribution regardless of the variation in the sample of the variables

8 0
3 years ago
Questo
Hitman42 [59]

Answer: (740)((1+0.0065)^132-1)/(0.0065)(1+0.0065)^132

Step-by-step explanation:

4 0
3 years ago
What is the value of x un the following equation: <br> -5.5x + 0.56 = -1.64
Ksenya-84 [330]
To solve this, you must subtract .56 from -1.64. Then divide that by -5.5x. So the answer is .4
8 0
3 years ago
About 7% of the population of a large country is nervous around strangers. If two people are randomly selected, what is the prob
chubhunter [2.5K]

Answer:

Probability both are nervous around strangers = 0.0049

Probability at least one is nervous around strangers = 0.1302

Step-by-step explanation:

Let probability a person selected in the population is nervous around strangers = P

                                        P = 7%

                                        P = \frac{7}{100}

                                        P = 0.07

Let probability a person selected in the population is not nervous around strangers = P'

                                         P' = 1 - P

                                         P' = 1 - 0.07

                                         P' = 0.93

(i) probability of the first person selected is nervous around strangers = P

   probability of the second person selected is nervous around strangers = P

   Probability both are nervous around strangers = (P × P)

                                         = 0.07 × 0.07

                                         = 0.0049

(ii) Probability at least one is nervous around strangers = ( probability the first person is nervous around strangers AND the second person is not nervous around strangers ) OR ( probability the second person is nervous around strangers AND the first person is not nervous around strangers)

This implies,

Probability at least one is nervous around strangers = (P × P') or (P × P')

                                        = (0.07 × 0.93) + (0.07 × 0.93)

                                        = 0.0651 + 0.0651

                                        = 0.1302

5 0
4 years ago
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