Which decimal is equivalent to 25/6 ?

On number 19 this needs to be shown full work I don’t know where to start can someone help me now ASAP!!!

DENIUS [597]

Answer:

1

sorry if I'm wrong, I'm in the 7th grade lol, did my best :) hope I sortof helped

Step-by-step explanation:

5-2=3

square root of 3 with 3 is 1

$5 - 2 = 1 \\ 3 \sqrt{3 = 1}$

7 0

2 years ago

dale has a square garden. He adds a 2-foot-wide walkway around his garden. If the total area of the walkway and garden is 196 sq

dem82 [27]

Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:

1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.

The total walkway area is thus x^2 + 4(2^2) + 4(x*2).

We want to find the dimensions of the garden. To do this, we need to find the value of x.

Let's sum up the garden dimensions and the walkway dimensions:

x^2 + 4(2^2) + 4(x*2) = 196 sq ft

x^2 + 16 + 8x = 196 sq ft

x^2 + 8x - 180 = 0

(x-10(x+18) = 0

x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.

The garden dimensions are (10 feet)^2, or 100 square feet.

4 0

3 years ago

Is matrix multiplication comutative?

konstantin123 [22]

Answer:

Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.

The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

$A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]$