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VikaD [51]
3 years ago
11

Can you help me please?

Mathematics
2 answers:
Ymorist [56]3 years ago
8 0
Make sure that you are looking at the right boxes
denis-greek [22]3 years ago
3 0

Answer:

Step-by-step explanation:

P1(0, -4)

m=1/2(1 up and 2 right)  

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Given the true/false statements are true (facts), select the best logical induction made from thoses statements: Mo likes orange
bekas [8.4K]

Answer:

People like oranges

Step-by-step explanation:

Given:

Mo likes oranges. Jai likes oranges. Ben likes oranges.

We have a few different options;

Option A: People don't like other fruit, such as apples. This can't be possible because we have only been given people who like oranges.

Option B: People on like oranges. This can't be possible because only is the case where people do not like any fruit except oranges, and we are not sure of this.

Option C: People like oranges. This can be possible because Mo, Jai, and Ben likes oranges

Option D: People like fruit. This can't be possible because we are not sure if people like all fruits or not

6 0
3 years ago
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
The length of a side of an equilateral triangle is 40cm. what is the length of the altitude of the triangle?
podryga [215]

Answer:

20√3 cm

Step-by-step explanation:

Altitude of an equilateral triangle splits it into 2 equal right triangles, it bisects the base and the angle opposite to the base.

<u>Let the altitude be x. Then as per Pythagorean theorem:</u>

  • x² = 40² - (40/2)²
  • x²= 1600 -400
  • x²= 1200
  • x= √1200
  • x= 20√3 cm

<u>Correct choice is</u> the second one

4 0
4 years ago
Which numbers are 9 units from −5 on this number line?
ExtremeBDS [4]

Using the number line, the numbers that are 9 units from -5 are: -14 and 4.

<h3>How to Locate a Number on a Number line?</h3>

To find two numbers that cover the same units from a given point on a number line, we can simply do the following:

  • Count the number of units given backwards/to the left from the point stated to get the first number.
  • Count the number of units given forwards/to the right from the point stated to get the second number.

Thus, we are asked to find the numbers that would be 9 units from -5, using the number line.

Count 9 units backwards/to the left from -5 to get the first number, which is: -14

Count 9 units forwards/to the right from the -5 to get the second number, which is: 4.

Therefore, the numbers that are 9 units from -5 on the number line, are: -14 and 4.

Learn more about number line on:

brainly.com/question/24644930

#SPJ1

8 0
2 years ago
Solve for x: 4(2x − 1) = 2x + 35
PilotLPTM [1.2K]
X = 13/2 or 6 1/2. Hope this helps!
7 0
4 years ago
Read 2 more answers
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