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Pavlova-9 [17]
2 years ago
9

Is this even possible

Computers and Technology
2 answers:
weeeeeb [17]2 years ago
8 0

Answer:

yes

Explanation:

The fastest WPM was 216 wpm

dimulka [17.4K]2 years ago
6 0

Answer:

Yes it is

Explanation: Because the 96 is how fast you typed and the 100 is what words you typed correctly.

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Comments can be hidden by clicking the _____ button.
Tamiku [17]
C because previous sends you back to something before such as a web page, Next does the opposite and I can't remember what Show MarkUp does.

5 0
3 years ago
PLEASE PLEASE HELP. IF THERE A MULTUPLE ANSWERS I WILL BRAINLIEST TO THE BEST ONE!!!!
sladkih [1.3K]

Answer: multiple answers but here is one

Explanation: The Advantages

One of the biggest advantages of ebooks is the fact that they require no trees to create them. This is obviously an eco-friendly option that both reduces cost and lowers environmental impact.

Information can be obtained without leaving your desk! Need to do some last-minute research on a particular topic? Simply find a great ebook store, search for your keywords or phrases, purchase the book and you’re set!

Unlike paper books and materials, digital books only require one device to carry around with you. This means you can carry a library of various book genres for every mood.

eBooks can lower the cost of enjoying your favorite titles. With no shipping and handling costs, eBooks typically have prices that are 50-60% lower than their print counterparts.

eBooks are more flexible than paper books. For those who have trouble reading the typical book-sized font, ebook readers can enlarge the font size to make reading more pleasurable and easier on the eyes.

eBooks can contain multi-media elements not available with traditional books. Audio and video can be embedded to make reading a fully immersive experience.

Ever wonder where that great passage in your favorite book went to? With ebooks you can mark passages, save pages and search text before, during or after you read.

With all these advantages it is difficult to imagine what the disadvantages are, but there are some that have many folks concerned. If you're already sold, we've listed the cheapest prices for the Amazon Kindle below.

The Disadvantages

Piracy is the number one concern for both publishers and authors. While traditional books can be copied with machines, the time and cost of doing so typically keeps this type of piracy at bay. With ebooks, however, 'sharing' books that have not been purchased with others is as easy as posting a file online or, in some cases, copying and pasting the text from one document to another.

Many people still prefer being able to hold a traditional book in their hands. For those of us who enjoy reading a book in bed before signing off for the night, a cold hard digital device just won’t be the same.

While one advantage of ebook devices is their ability to enlarge fonts for easier reading, the fact is you are still reading off an LCD screen. Some readers have matte e-ink screens, but others give off a glare that can not only make reading inconvenient if the lighting isn’t just right, but may actually cause eye strain and make it more difficult to focus while reading.

With the wide variety of formats and ereader devices on the market, choosing which device is the right one for all situations can be nearly impossible. Though compatible formats have been introduced that should allow most readers to view purchases, many of these still lack proper formatting. Without proper page layouts and spacing reading becomes more of a tedious chore than an enjoyable pastime. With traditional books one simply buys and reads!

When is the last time you had to plug your paper book into the wall outlet? How disappointing would it be to find yourself right in the middle of a steamy romance scene while traveling only to have the batteries in your reading device die, with no way to charge them?

Currently, ebooks have an unreliable life span. Paper books last for decades provided they are well cared for. And besides, what good is a bookshelf if you cannot enjoy the look and smell of all your time-worn books, lovingly thumbed, crimped and read cover to cover, over and over again?

7 0
2 years ago
Referring to the BST and BSTNode classes for binary search trees as done in class: Determine the result of executing root. whate
Rzqust [24]

Answer:

Try to add allthe numbers up

Explanation:

3 0
3 years ago
You are tasked to calculate a specific algebraic expansion, i.e. compute the value of f and g for the expression: ???? = (??????
melisa1 [442]

Answer:

.data

prompt: .asciiz "Enter 4 integers for A, B, C, D respectively:\n"

newLine: .asciiz "\n"

decimal: .asciiz "f_ten = "

binary: .asciiz "f_two = "

decimal2: .asciiz "g_ten = "

binary2: .asciiz "g_two = "

.text

main:

#display prompt

li $v0, 4

la $a0, prompt

syscall

#Read A input in $v0 and store it in $t0

li $v0, 5

syscall

move $t0, $v0

#Read B input in $v0 and store it in $t1

li $v0, 5

syscall

move $t1, $v0

#Read C input in $v0 and store it in $t2

li $v0, 5

syscall

move $t2, $v0

#Read D input in $v0 and store it in $t3

li $v0, 5

syscall

move $t3, $v0

#Finding A^4

#Loop (AxA)

li $t6, 0

L1:

bge $t6, $t0, quit

add $s1, $s1, $t0 # A=S+A => $s1= A^2

addi $t6, $t6, 1 # i=i+1

j L1

quit:

#Loop (A^2 x A^2)

li $t6, 0

L1A:

bge $t6, $s1, quit1A

add $s5, $s5, $s1

addi $t6,$t6, 1

j L1A

#End of Finding A^4

#Finding 4xA^3

quit1A:

#Loop (4xB)

li $t6, 0

L2:

bge $t6, 4, quit2

add $s2, $s2, $t1

addi $t6, $t6, 1

j L2

quit2:

#Loop (BxB)

li $t6 , 0

L2A:

bge $t6, $t1, quit2A #loop2

add $s6, $s6, $t1 #add

addi $t6, $t6, 1 #add immediate

j L2A #loop2

quit2A: # perform proper program termination using syscall for exit

#Loop (BxB)

li $t6 , 0 #load immediate

L2AA:

bge $t6, $s2, quit2AA #loop2

add $t7, $t7, $s6 #add

addi $t6, $t6, 1 #add immediate

j L2AA #loop2

#End ofFinding 4xA^3

#Finding 3xC^2

quit2AA: # perform proper program termination using syscall for exit

#3 Loop (3 x (C x C)) FOR S3

li $t6 , 0 #load immediate

L3:

bge $t6, $t2, quit3 #loop3

add $s3, $s3, $t2 #add

addi $t6,$t6, 1 #add immediate

j L3 #loop3

quit3: # perform proper program termination using syscall for exit

#3 Loop (3 x (C x C)) FOR S3

li $t6 , 0 #load immediate

L3A:

bge $t6, 3, quit3A #loop3

add $s0, $s0, $s3 #add

addi $t6,$t6, 1 #add immediate

j L3A #loop3

#End of Finding 3xC^2

#Finding 2xD

quit3A: # perform proper program termination using syscall for exit

#4 Loop (2 x D) FOR S4

li $t6 , 0

L4:

bge $t6, 2, quit4 #loop4

add $s4, $s4, $t3 #add

addi $t6, $t6, 1 #add immediate

j L4 #Loop4

#End of Finding 2xD

#Finding AxB^2

quit4:

li $t6, 0

li $s1, 0

L5:

bge $t6, $t1, quit5

add $s1, $s1, $t1

addi $t6, $t6, 1

j L5

quit5:

li $t6, 0

li $s2, 0

L6:

bge $t6, $t0, quit6

add $s2, $s2, $s1

addi $t6, $t6, 1

j L6

#End of Finding AxB^2

#Finding C^2XD^3

quit6: #finds C^2

li $t6, 0

li $s1, 0

L7:

bge $t6, $t2, quit7

add $s1, $s1, $t2

addi $t6, $t6, 1

j L7

quit7: #finds D^2

li $t6, 0

li $s6, 0

L8:

bge $t6, $t3, quit8

add $s6, $s6, $t3

addi $t6, $t6, 1

j L8

quit8: #finds D^3

li $t6, 0

li $s7, 0

L9:

bge $t6, $t3, quit9

add $s7, $s7, $s6

addi $t6, $t6, 1

j L9

quit9: #finds C^2XD^3

li $t6, 0

li $s3, 0

L10:

bge $t6, $s1, end

add $s3, $s3, $s7

addi $t6, $t6, 1

j L10

#End of Finding C^2XD^3

end: # perform proper program termination using syscall for exit

#f is $t8

li $t8 , 0

sub $t8, $s5, $t7 # addition

add $t8, $t8, $s0 # subract

sub $t8,$t8, $s4 # subract

#g is $t9

li $t9 , 0

add $t9, $s2, $s3 # addition

#Display

#1st equation

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, decimal # Gives answer in decimal value

syscall # value entered is returned in register $v0

li $v0, 1 # display the answer string with syscall having $v0=1

move $a0, $t8 # moves the value from $a0 into $t8

syscall # value entered is returned in register $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, newLine # puts newLine in between answers

syscall # value entered is returned in register $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, binary # Gives answer in binary

syscall # value entered is returned in register $v0

li $v0, 35

move $a0, $t8 # moves the value from into $a0 from $t8

syscall # value entered is returned in register $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, newLine # puts newLine in between answers

syscall # value entered is returned in register $v0

#2nd equation

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, decimal2 # Gives answer in decimal value

syscall # value entered is returned in register $v0

li $v0, 1 # display the answer string with syscall having $v0=1

move $a0, $t9 # moves the value from $a0 into $t8

syscall # value entered is returned in reg $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, newLine # puts newLine in between answers

syscall # value entered is returned in register $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, binary2 # Gives answer in binary

syscall # value entered is returned in register $v0

li $v0, 35

move $a0, $t9 # moves the value from into $a0 from $t8

syscall # value entered is returned in register $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, newLine # puts newLine in between answers

syscall # value entered is returned in register $v0

#end the program

li $v0, 10

syscall

8 0
2 years ago
Write a class definition line and a one line docstring for the class Dog. Write an __init__ method for the class Dog that gives
Viefleur [7K]
Python Code:

class Dog:
""" Dog class definition """

# data attribute species as part of the class Dog
species = "Canis familiaris"

def __init__(self, _name, _breed):
""" Constructor """
# Assigning values
self.name = _name
self.breed = _breed
self.tricks = []

def teach(self, trick):
""" add a passed string parameter to tricks """
# Adding to list
self.tricks.append(trick)
# Printing message
print(self.name + " knows " + trick)


def knows(self, chkStr):
""" check whether a passed string parameter is in the dog’s list of tricks """
# Checking in tricks list
if chkStr in self.tricks:
# Printing message
print("Yes, " + self.name + " knows " + chkStr)
else:
# Printing message
print("No, " + self.name + " doesn't know " + chkStr)
4 0
2 years ago
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