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Novay_Z [31]
3 years ago
10

How many solutions are there to the equation

Mathematics
1 answer:
klasskru [66]3 years ago
5 0
One? Bc you get x=1 when you get 3x-5=2x-3-x then 2x-5=-3 then 2x=2
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Please help on number 20!
Tom [10]
Answer: 32.67 cm


Explanation:

Circumference = πD
Circumference = π(10.4)
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7 0
3 years ago
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Which of the following numbers is different
nadezda [96]

Answer:

(D) 1/4%

hope that helps uh..☺

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Write an equation to represent the proportional relationship between the # of Vegetable Plants (x) and the # of Flowers (y).
yawa3891 [41]

Answer:

Proprortional Value is equal to 2/3 or 2:3

Step-by-step explanation:

4/6=2/3

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6 0
3 years ago
Crecimiento de arboles
denpristay [2]

Queremos encontrar la altura de las plantas luego de t años, dado que conocemos la altura inicial y la velocidad de crecimiento.

La ecuación de la altura es:

h(t) = 0.75*t^2 + 5*t + 12

Con ella veremos que los arbustos miden 69cm cuando son vendidos.

<em>Veamos como resolver esto.</em>

h(t) es la función que modela la altura de las plantas.

Sabemos que:

\frac{dh(t)}{dt} = 1.5*t + 5

Sí integramos, obtendremos:

h(t) = (1/2)*1.5*t^2 + 5*t + c

donde C es una constante de integración, la cual representa la altura inicial (para t = 0) de las plantas, notar que:

h(0) = c

Y sabemos que las plantas miden 12 cm cuando son plantadas, entonces c = 12.

La ecuación de la altura es entonces:

h(t) = 0.75*t^2 + 5*t + 12

Esta ecuación nos da la altura en centimetros a tiempo t.

Sabemos que los arbustos se venden luego de 6 años, entonces la altura que tendran cuando son vendidos es:

h(6) = 0.75*6^2 + 5*6 + 12 = 69

Es decir, los arbustos miden 69cm cuando son vendidos.

Sí quieres aprender más, puedes leer.

brainly.com/question/25180768

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If, for all x, f'(x)=(x-2)^4(x-1)^3, it follows that funtaion f has
Elenna [48]

Answer:

We say that f(x) has an absolute (or global) minimum at x=c if f(x)≥f(c) f ( x ) ≥ f ( c ) for every x in the domain we are working on. We say that f(x) has a relative (or local) minimum at x=c iff(x)≥f(c) f ( x ) ≥ f ( c ) for every x in some open interval around x=c .

4 0
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