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3 years ago

Please help cktfghdjgdjhfxcvbgghjbfjv

Mathematics

1 answer:

olchik [2.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

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What is the coordinates after (x+2, y + 3)

emmainna [20.7K]

Answer:

L is (2,4) M (3,1,) N(0,4)

Step-by-step explanation:

L 0+2=2 so x is 2

L 1+3=4 so y is 4

M 1+2=3 so x is 3

M -2+3=1 so y is 1

N -2+2=0 so x is 0

N 1+3=4 so y is 4

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20x%20-%202%5Csqrt%7Bx%20-%203%20%3D%200%7D%20" id="TexFormula1" title=" x - 2\sqrt{x - 3 = 0

GrogVix [38]

Answer:

No Real Solutions

Step-by-step explanation:

So we have:

$x-2\sqrt{x-3}=0$

First, determine the domain restrictions. The expression under the radical cannot be less than 0. Therefore:

$x-3\geq 0\\x\geq 3$

Therefore, our final answers must be greater than or equal to 3:

Now, going back to the original equation, subtract x from both sides:

$-2\sqrt{x-3}=-x$

Now, square both sides:

$4(x-3)=x^2$

Distribute:

$4x-12=x^2$

Subtract 4x and add 12 to both sides:

$0=x^2-4x+12$

This isn't factor-able. Let's use the quadratic formula. a is 1, b is -4 and c is 12:

$x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Substitute:

$x=\frac{4\pm\sqrt{(-4)^2-4(1)(12)}}{2(1)}$

Simplify the radical:

$x=\frac{4\pm\sqrt{-32}}{2(1)}$

The number under the radical is negative. In other words, there are no real solutions.

7 0

3 years ago

Find the midpoint between A and B, given that A=(-1,5) and B=(-3,-7)

Kamila [148]

Hello here is a solution :
<span> midpoint between A and B,is :C( (Xa+xb)/2; (ya+yb)/2)
C( (-1-3)/2;(5-7)/2)
C(-2 ; -1)</span>

6 0

3 years ago

The telephone company offers two billing plans for local calls. Plan 1 charges $29 per month for unlimited calls and Plan 2 char

PilotLPTM [1.2K]

Answer:

$79.20

Step-by-step explanation:

fixed charged of $19 x 4 months = $76.00

additional charged of $0.04 x 20 = $0.80 x 4 months = $3.20

Therefore, $76.00 + $3.20 = $79.20

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3 years ago

What is the product of? (7x^2)(2x^3+5)(x^2-4x-9)

pav-90 [236]

$(7x^{2})(2x^{3} +5)( x^{2} -4x-9)
$
$(14 x^{5} +35 x^{2})( x^{2} -4x-9)$
= $14 x^{7} -56 x^{6}-126 x^{5}+35 x^{4}-140 x^{3}-315 x^{2}$

6 0

3 years ago

Read 2 more answers