Answer:
Jenna sold 280 boxes, Becca sold 105 boxes.
Step-by-step explanation:
For every 3 boxes B sold, J sold 8 boxes and ended with a total of 385 boxes sold.
3b+8j=385
From how the question is asked, we can assume that each round of sales would equal 11 total sales. (3b+8j=11)
Knowing the sales take place in intervals of 11, we can solve the problem by doing 385/11.
385/11=35
Finally, with 35 rounds of sales happening and knowing Jenna sells 8 while Becca sells 3 at each one, all that's left to do is multiply.
8x35=280
3x35=105
To be sure we can check our answer by adding them together, 280+105=385.
139, 149, 159, 169, 179, 189, 199, 209, 219, 229, 239, 249, 259.
The common difference is 13.
Let n = 52
Let d = common difference
a_52 = 139 + (52 - 1)(13)
a_52 = 139 + (51)(13)
a_52 = 139 + 663
a_52 = 802
1. D none of the above.
2. A 5.43, 5.62, 5.74
3. A 75%
4. A 87.5%
5. A 0.7
6. B between 0.5 and 1.0
