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Maslowich
2 years ago
12

Dixie drinks 1/3 a cup of water in 1/6 of a minute. How many cups of water per minute does Dixie drink?

Mathematics
2 answers:
natka813 [3]2 years ago
6 0
2 drinks! Can I pls have brainliest??
Alex73 [517]2 years ago
6 0

Hello, 928747! I can help.

So, we're trying to find out how many cups of water Dixie can drink per minute.

Since there are 60 seconds in a minute, we can assume that 1/6 of a minute is 10 seconds

1/6 = 10/60

So there are 60 seconds in a minute so we would multiply 1/3 by 6 to find how many cups she can drink in one minute

1/3 x 6 = 2

So, Dixie can drink 2 cups in one minute.

#LearnWithBrainly

<u>brainly.com/question/21742939</u>

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A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th
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Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

A = a + (A \cap B)

In which a is the probability that he wins the first race but not the second and A \cap B is the probability that he wins both these races.

By the same logic, we have that:

B = b + (A \cap B)

The probability that he wins both races is 0.5.

This means that A \cap B = 0.5

The probability that he wins the second race is 0.6

This means that B = 0.6

B = b + (A \cap B)

0.6 = b + 0.5

b = 0.1

The probability that he wins the first race is 0.7.

This means that A = 0.6

A = a + (A \cap B)

0.7 = a + 0.5

a = 0.2

A) he wins at least one race.

This is

P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

P = a + b = 0.2 + 0.1 = 0.3

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

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Which statement is true about the solution ?
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