Answer:
Distance between point 
and midpoint of line joining 
and 
= 
units.
Step-by-step explanation:
Given:
Points:
To find distance from point A to midpoint of BC.
Midpoint M of BC:
[Plugging in points 
]
Distance between A and M:
[Plugging in points 
]
Since distance is always positive ∴ 
units
Answer:
x = 14.5 y = 1
Step-by-step explanation:
get the x alone by subtracting 5y from both sides
10x + 5y = 150
- 5y -5y
10x = -5y + 150
divide both sides by 10
<u>10x</u> = <u>-5y + 150</u>
10 10
x = -0.5y + 15
Now that we've solved for x, we can plug it into the original equation
10 (-0.5y + 15) + 5y = 150
now we solve for y the same way we did x
first distribute 10 into (-0.5y + 15)
-5 + 150 +5y = 150
now we get the y alone
-5 + 150 + 5y = 150
+5 -150 -150 +5
5y = 5
now divide by 5
<u>5y</u> = <u>5</u>
5 5
y = 1
now that we have both x and y, we plug y into our solution for x
x = -0.5y + 15
x = -0.5(1) + 15
x= -0.5 + 15
x = 14.5
Hayya please help with mine its right above
