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Very complex, you should ask each individual question, or give more points
general strategy:
get 1 side to equal 0
factor
set each factor to 0
solve
1. factor out the x and set each to zero
x(x+7)=0
x=0
x+7=0
subtract 7
x=-7
x=0 or -7
2. factor out the 6s
6s(s+3)=0
6s=0
s=0
s+3=0
subtract 3
s=-3
s=-3 or 0
3. I'm assuming that the equation was supposed to be t^2+8t+16 so
find what 2 numbers multiply to get 16 and add to get 8
the numbers are 4 and 4
factor
(x+4)(x+4)=0
x+4=0
subtract 4
x=-4
4. find what 2 numbers multipy to get 25 and add to get -10
the numbers are -5 and -5
factor
(x-5)(x-5)=0
set each to zero
x-5=0
add 5
x=5
5. subtract 16 from both sides
h^2+6h-16=0
find what 2 numbers multiply to get -16 and add to get 6
the numbers are -6 and 10
factor
(h-6)(h+10)=0
set each to zero
h-6=0
add 6
h=6
h+10=0
subtract 10
h=-10
h=-10 or 6
6.subtract 5x from both sides
x^2-5x-14=0
find what 2 numbers multiply to get -14 and add to get -5
the numbers are -7 and 2
factor
(x-7)(x+2)=0
set each to zero
x-7=0
add 7
x=7
x+2=0
subtract 2
x=-2
x=-2 or 7
7.add 2r^2 to both sides
2r^2+11r+15=0
difficult so multiply 2 and 15 and get 30
not factor and find what 2 numbers multiply to get 30 and add to get 11
the numbers are 5 nd 6
split 11 up into 5 and 6
2r^2+6r+5r+15=0
group and factor
(2r^2+6r)+(5r+15)=0
factor
2r(r+3)+5(r+3)=0
reverse distribute
(2r+5)(r+3)=0
set each to zero
2r+5=0
subtract 5
2r=-5
divide 2
r=-5/2
r+3=0
subtract 3
r=-3
r=-3 or -5/2
8. this is a difference of 2 perfect squares in which if you have
x^2-y^2 that factors out of (x-y)(x+y) so
x^2-25=0
x^2-5^2=0
(x-5)(x+5)=0
set each to zero
x-5=0
add 5
x=5
x+5=0
subtract 5
x=-5
x=-5 or 5
9. differnce of 2 perfect squares
81-4x^2=0
9^2-(2x)^2=0
(9-2x)(9+2x)=0
set each to zero
9-2x=0
add 2x to both sides
9=2x
divde 2
9/2=x
9+2x=0
subtract 9 from both sidees
2x=-9
divide 2
x=-9/2
x=-9/2 or 9/2
10. subtract 12s from both sides
4s^2-12s+9=0
multiply 4 and 9 and get 36
find what 2 numbers multiply to get 36 and add to get -12
the numbers are -6 and -6
split up the -12s into -6s and -6s
4s^2-6s-6s+9=0
group
(4s^2-6s)+(-6s+9)=0
factor
2s(2s-3)+(-3)(2s-3)=0
reverse distribute
(2s-3)(2s-3)=0
set each to zero
2s-3=0
add 3
2s=3
divide 2
s=3/2
ANWERS:
1. x=0 or -7
2. s=-3 or 0
3. x=-4
4. x=5
5. h=-10 or 6
6. x=-2 or 7
7. r=-3 or -5/2
8. x=-5 or 5
9. x=-9/2 or 9/2
10. s=3/2
Answer:
0.38
Step-by-step explanation:
Please Mark Brainliest
Answer:
8008
Step-by-step explanation:
nCr=16!/6!*(16-6)!=8008
If the slope is greater than one, it would have a positive slope and it is moving vertically up the y axis.
<em>If the slope is equal to one, Guessing that the y axis is counting by 1 you could tell the slope is 1 by looking to see if first, it is moving positively up the y axis or look at what points it is intersecting. If it's counting every 1 point (For example) If the start of the slope began on the origin (0, 0) than it should count (0, 0) - (1, 1) - (2, 2) - (3, 3) etc..</em>
<u>Now the more "confusing" one. if the slope is less than one it can be a flat line on the graph. Not negative nor positive, Its neutral. You can also tell if its positive if it is moving down the graph, Negatively. or if it is moving into a different quadrant from. (0, 0)</u>
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The different fonts are the different answers, i hope this helped.